C language learning supplementary pointer * p ++, (* p) ++, * difference ++ p, ++ * p of

#include <stdio.h>
 int main () 
{ 
    int A [ . 5 ] = { . 1 , 2 , . 3 , 4 , . 5 };
     int * p = & A [ . 3 ]; // where p points to the array element of the fourth 4 the starting address.
    p = * 100 ; 
    the printf ( " % D \ n- " , * p ++ ); // take the first value p at 100 , and then to increment the pointer p. 1;
     the printf ( " % D \ n- " , the P-- * ); // 
    the printf ( " % D \ n- " , * - p); // first pointer p 1 is decremented, and then take the value pointed to
    return 0;
}
// 100 5 3 

* P ++, (* p) ++, * difference ++ p, ++ * p of

 int a[5]={1,2,3,4,5};

p = A * int; 

* p ++ to take the value of the pointer p points ( the first element of the array 1), and then increment the pointer p 1 ; 

        COUT << * p ++; // result is 1 

        COUT << (* p ++); 1 // 

(* p) ++ p points go pointer value (a first element of the array), then the value is incremented by one (becomes the first element of the array 2 
        COUT << (* p) ++ ; // 1 
        COUT << ((* p) ++) // 2 
* p ++    first pointer p is incremented by one (in this case points to the second element of the array), * and then taken out of the operation value

         cout << * p ++; // 2 
        COUT << (* p ++) // 2 

++ * p   to take the value of the pointer p points (the first array element 1), then the value is incremented by one (the first array element becomes 2) 
      cout << * P ++; 2 //     
        cout << (* P ++) // 2 

Note that the above cout each output to a separate output to get the results back. 
string pointer

#include <stdio.h>
int main()
{
    char buffer[10]="ABC";
    char *pc;
    pc="hello";
    printf("%s\n",pc);
    pc++;
    printf("%s\n",pc);
    printf("%c\n",*pc);
    pc=buffer;
    printf("%s\n",pc);
    return 0;
 } 

 

 

#include <stdio.h>
int main()
{
    int a[4]={1,3,5,7};
    printf("%p\n",a);
    printf("%p\n",a+1);
    printf("%p\n",&a);
    printf("%p\n",&a+1);
    printf("%p\n",*(&a));
    printf("%p\n",*(&a)+1);
    return 0;
}

 

 

 

p = A * int; 

* p ++ to take the value of the pointer p points ( the first element of the array 1), and then increment the pointer p 1 ; 

        COUT << * p ++; // result is 1 

        COUT << (* p ++); 1 // 

(* p) ++ p points go pointer value (a first element of the array), then the value is incremented by one (becomes the first element of the array 2 
        COUT << (* p) ++ ; // 1 
        COUT << ((* p) ++) // 2 
* p ++    first pointer p is incremented by one (in this case points to the second element of the array), * and then taken out of the operation value

         cout << * p ++; // 2 
        COUT << (* p ++) // 2 

++ * p   to take the value of the pointer p points (the first array element 1), then the value is incremented by one (the first array element becomes 2) 
      cout << * P ++; 2 //     
        cout << (* P ++) // 2 

Note that the above cout each output to a separate output to get the results back. 
string pointer

#include <stdio.h>
int main()
{
    char buffer[10]="ABC";
    char *pc;
    pc="hello";
    printf("%s\n",pc);
    pc++;
    printf("%s\n",pc);
    printf("%c\n",*pc);
    pc=buffer;
    printf("%s\n",pc);
    return 0;
 } 

 

 

#include <stdio.h>
int main()
{
    int a[4]={1,3,5,7};
    printf("%p\n",a);
    printf("%p\n",a+1);
    printf("%p\n",&a);
    printf("%p\n",&a+1);
    printf("%p\n",*(&a));
    printf("%p\n",*(&a)+1);
    return 0;
}