Tarjan-CV / BCC / SCC algorithm study notes

Application of DFS Properties - Use Tarjan algorithm for cutting the top, BCC, SCC

Since finishing "algorithm contest entry classic training manual" as well as network

DFS (depth first search) depth-first search algorithm

Forest dfs: dfs execution order of all the edges of the graph to comb, into four categories: the front side, reverse side, and cross edge side of the tree. There is no cross-free edges to the graph, is equivalent to the forward side and the rear side.

pre value in the DFS process, u and their descendants can connect back to the earliest ancestors: low [u]


  • Top cut: FIG For communication, so delete FIG no communication points .
  • Bridge: FIG For communication, so delete FIG no communication side .

The method of calculating the cutting top: the DFS process, a point if there is one child node v u, v and their descendants that are not connected back to the reverse side of the ancestors of u (u is not included), i.e. lowv> = pre [u] , then u is cut top.

The method of calculation of the bridge: If you can only link back to the descendants of v v themselves (ie low (v)> pre (u)) is the uv bridge.

note:

1. For the access point has only the reverse side processing (condition pre [v] <pre [u ]).
2. For special sentenced to roots, when a child is not only cut the top, you need to manually cancel cut the top mark.

  • No Twin connected component (points):, i.e., without any internal cutting edges in the top two in a simple ring.
  • Undirected graph edges - bis connected components: all edges are not bridged, i.e. each edge are at least in a simple ring.

The method of calculation of the BCC: the edge of the stack, will be found after cutting the top edge of this side of the stack onto the stack, marker.

Method of calculating the edge-BCC: finding a bridge and then do not go through DFS to bridge.

  • The strongly connected component: up to each point within the component

The method of calculating the SCC: the point stack, DFS recorded during lowlink, when lowlink (u) == pre (u) to the point where the stack tag.

note:

1. When you reach a point of access have been determined to ignore the number of points (conditions! Sccno [v])
2. a minimum value can take any (relatively small roots)

lowlinku = min(lowlinku, pre[v] OR lowlinkv);

Paste the code

BCC calculation
#include <iostream>
#include <stack>
#include <vector>
#include <algorithm>
using namespace std;

const int maxn = 2e4 + 1;
int dfs_clock, pre[maxn], iscut[maxn], bccno[maxn], bcc_count;
struct Edge {
    int u, v;
};
vector <int> bcc[maxn], G[maxn];
stack <Edge> S;
void AddE(int u, int v) {
    G[u].push_back(v);
}
int tarjan(int u, int fa) {
    int lowu = pre[u] = ++dfs_clock, child = 0;
    for (auto v: G[u]) {
        if (!pre[v]) {
            child++;
            S.push((Edge) {u, v});
            int lowv = tarjan(v, u);
            lowu = min(lowu, lowv);
            if (lowv >= pre[u]) {
                iscut[u] = 1;
                ++bcc_count;
                bcc[bcc_count].clear();
                //cout<<dfs_clock<<' '<<u<<'>'<<v<<','<<lowv<<'|'<<bcc_count<<endl;
                while (1) {
                    Edge e = S.top();   S.pop();
                    if (bccno[e.u] != bcc_count) {
                        bcc[bcc_count].push_back(e.u);
                        bccno[e.u] = bcc_count;
                    }
                    if (bccno[e.v] != bcc_count) {
                        bcc[bcc_count].push_back(e.v);
                        bccno[e.v] = bcc_count;
                    }
                    if (e.u == u && e.v == v)   break;
                }
            }
        } else if (pre[v] < pre[u] && v != fa) {
            S.push((Edge) {u, v});
            lowu = min(lowu, pre[v]); //Err
        }
    }
    if (fa == -1 && child == 1) iscut[u] = 0; //Err
    return lowu;
}
signed main() {
    int n, m, u, v, i;
    cin>>n>>m;
    while (m--) {
        cin>>u>>v;
        AddE(u, v);
        AddE(v, u);
    }
    for (i = 1; i <= n; ++i)
        if (!pre[i])
            tarjan(i, -1);
    cout<<count(iscut + 1, iscut + n + 1, 1)<<endl;
    for (i = 1; i <= n; ++i)
        if (iscut[i])
            cout<<i<<' ';
    return 0;
}

Tarjan seeking the SCC + + condensing point Topological Sort

#include <iostream>
#include <vector>
#include <stack>
using namespace std;

const int maxn = 1e4 + 1;
int n;
int pre[maxn], dfs_clock, sccno[maxn], scc_count;
int c[maxn << 1], topo[maxn << 1], cnt;
vector <int> G[maxn], GA[maxn], scc[maxn];
stack <int> S;
void AddE(int u, int v) {
    G[u].push_back(v);
}
void AddED(int u, int v) {
    GA[u].push_back(v);
}
int tarjan(int u) {
    int lowlinku = pre[u] = ++dfs_clock;
    S.push(u);
    for (auto x: G[u])
        if (!pre[x]) {
            int lowlinkv = tarjan(x);
            lowlinku = min(lowlinku, lowlinkv);
        } else if (!sccno[x])
            lowlinku = min(lowlinku, pre[x]);
    if (lowlinku == pre[u]) {
        ++scc_count;
        scc[scc_count].clear();
        while (1) {
            int v = S.top(); S.pop();
            scc[scc_count].push_back(v);
            sccno[v] = scc_count + n;
            if (v == u) break;
        }
    }
    return lowlinku;
}
int dfs(int u) {
    static int cnt = n + scc_count;
    if (c[u] == -1)
        return false;
    c[u] = -1;
    for (auto v: GA[u])
        if (!c[v] && !dfs(v))   return false;
    c[u] = 1;
    topo[cnt--] = u;
    return true;
}
int toposort(int n) {
    for (int i = 1; i <= n; ++i)
        if (!c[i])
            if (!dfs(i))
                return false;
    return true;
}

void sillys(int n) {
    int ans = 0, cnt;
    for (int i = n; i > 0; --i)
        if (G[topo[i]].empty()) {
            ans = topo[i];
            cnt++;
        }
    if (cnt == 0)
        cout<<"Fuck"<<endl;
    else if (cnt > 1)
        cout<<0<<endl;
        else if (cnt == 1) {
            if (ans <= n)
                cout<<1<<endl;
            else
                cout<<scc[ans - ::n].size()<<endl;
        }
    return;
}
signed main() {
    int m, i, u, v;
    cin>>n>>m;
    while (m--) {
        cin>>u>>v;
        AddE(u, v);
    }
    for (i = 1; i <= n; ++i) {
        tarjan(i);
        if (sccno[i] == 0)
            sccno[i] = i;
    }
    for (i = 1; i <= n; ++i)
        for (int v: G[i])
            AddED(sccno[i], sccno[v]);
    if (!toposort(n + scc_count))
        cout<<"Shit!"<<endl;
    sillys(n + scc_count);
    return 0;
}

To be added

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Origin www.cnblogs.com/Decisive/p/11498791.html