Simple recursive function

# Factorial of the number specified 
DEF SUM (n-): 
    IF n-==. 1: 
        return n- 
    the else: 
        return n-* SUM (. 1-n-) 
NUM = SUM (. 5) 
Print (NUM)

# 阶乘递归求和
def total_sum(m):
    total=0
    for i in range(1,m+1):
        def sum(n):
            if n==1:
                return n
            else:
                return n*sum(n-1)
        total+=sum(i)
    return total
num=total_sum(5)
print(num)