--- --- restore content begins
First, the index of the string and slice
1. Index
s = 'ASDFGHJKL'
Ordered sequence, index --index: from 0
s1 = s [0], remove the individual elements: A; s1 is independent of a string of new and original string
2. Slice
# Want to take ASDF:
s2 = s [0: 4] Law: care regardless Ding
# Want to take L:
s3 = p [-1]
# Want to take all
s4 = s[:] or s[0:]
s5 = s [0: -1], the last fail to
3. Take jumping, add step
s = 'ABCDLSESRF'
s6 = s [0: 5: 2] Take: ACL
4. Take the inverse
s7 = s [4: 0: -1] Take: LDCB
s8 = s [3 :: - 1] take: DCBA
s9 = s [3 :: - 2] taken: DB
s10 = s [-1 :: - 1] or s = [:: - 1] negated
Second, conventional methods of operation string
s = 'alexWUsir'
1. capitalized capitalize ()
s1 = s.capitalize()
2. All capitalized Upper () , all lowercase lower ()
s2 = s.upper()
s21 = s.lower () eg: Demand - codes insensitive, how to determine whether the correct input
3. Flip case swapcase ()
s3 = s.swapcase ()
4. spaced word capitalized (with spaces or special characters, numbers can be separated) title ()
s = alex egon wusir
s4 = s.title()
The center, add the total width of the filling; Center ()
s = 'alexWUsir'
s5 = s.center(20,' ')
6.8 a separated, not full complement, expandtabs ()
s = 'alex \ survivors'
s6 = s.expandtabs()
# Public Methods
len () --- seek length
7. Analyzing string beginning with what startwith (), the mirror method endwith (), returns True / False
s = 'alexWUsir'
s7 = s.startwith('alex') #True
s71 = s.startwith('e',2,5)
8. lookup indexed by elements not found returns -1 Find ()
s = 'alexWUsir'
s8 = s.find ( 'W') returns the index: a plurality of elements 4, with the first element index prevail
s8 = s.index('A')
9. Find the index through the elements, can not find the error index ()
10. Delete the default string trailing spaces , Strip ()
Not just a space, you can modify the default values. % *
Variants: rstrip (), lstrip () to delete the left to the right elements
11. statistics, count ()
s = 'alexWUsir'
s9 = s.count('al') # 1
12. The split, split, Split () into a list of strings turn list
s = 'alex WUsir taibai'
l = s.split () # default list is divided into a space
s = 'alex:WUsir:taibai'
l = s.split(':')
Delimiter will disappear (spaces: other delimiter of your choice)
13. formatted output, the format () three kinds of play
s = 'My name is {}, {year}, {} hobby, to tell you my name is {}'. format ( 'john', '18', 'ball', 'john') # correspondence
s = 'My name is {0}, {1} this year, hobbies, {2}, to tell you my name is {0}'. format ( 'john', '18', 'ball') # corresponding index
s = 'My name is {name}, this {age}, hobby {hobby}, to tell you my name is {name}'. format (age = 18, name = 'john', hobby = 'ball') # key-value pairs
14. Alternatively --replace () old new count
s = "view neighborhood See neighborhood milk remember to play."
s1 = s.replace ( "Block", "Wang") replace all default
15.is series
= name 'taibai123'
Print (name.isalnum ()) # string of letters or numbers
print (name.isalpha ()) # string contains only the alphabet
string print (name.isdecimal ()) # of only decimal composition
three, for loop
limit cycle, iterables
S = 'sdasfsfr'
for I in S:
Print (I)
