P3374 [template] Fenwick tree 1
Topic links: https://www.luogu.org/problem/P3374
topic:
If that is known to a number of columns, you need to perform the following two operations:
A number x plus 1. The
2. obtaining a number of sections and each
Input Format
The first line contains two integers N, M, respectively, represents the number of the total number of columns and number of operations.
The second line contains N integers separated by spaces, wherein the number indicates the i-th column of the item i of the initial value.
Next M lines contains three integers, it represents one operation, as follows:
Operation 1: Format: 1 XK Meaning: the number of x plus k
Operation 2: Format: 2 XY Meaning: the number of outputs of each interval [x, y] and the
Output Format
Output contains an integer number of lines, that is, the operation results of all 2.
Sample input and output
5 5 1 5 4 2 3 1 1 3 2 2 5 1 3 -1 1 4 2 2 1 4
14 16
Description / Tips
Constraints of time: 1000ms, 128M
Data Scale:
For 30% of the data: N <= 8, M <= 10
For 70% of the data: N <= 10000, M <= 10000
To 100% of the data: N <= 500000, M <= 500000
Sample Description:
14 and 16 so that the output
// // Created by hanjinyu on 19-9-2. // #include<bits/stdc++.h> using namespace std; typedef long long ll; const int maxn=1e6+10; int n,m; int ans; int input[maxn]; struct Node{ int left; int right; int num; }tree[maxn*4]; void PushUp(int index) { tree[index].num = tree[index<<1].num+tree[index<<1|1].num; } void build(int l,int r,int index) { tree[index].left=l; tree[index].right=r; if(l==r) { tree[index].num = input[l]; return; } int mid=(l+r)>>1; build(l,mid,index<<1); build(mid+1,r,index<<1|1); PushUp(index); } void change(int index,int dis,int k) { if(tree[index].left==tree[index].right) { tree[index].num += k; return; } if(dis<=tree[index<<1].right) change(index<<1,dis,k); else change(index<<1|1, dis, k); PushUp(index); } void search(int index,int l,int r) { if(l<=tree[index].left&&r>=tree[index].right) { ans+=tree[index].num; return; } if(tree[index<<1].right>=l) search(index<<1,l,r); if(tree[index<<1|1].left<=r) search(index<<1|1,l,r); } int main() { scanf("%d%d",&n,&m); for(int i=1;i<=n;i++) { scanf("%d",&input[i]); } build(1,n,1); int x,y,z; for(int i=1;i<=m;i++) { scanf("%d%d%d",&x,&y,&z); if(x==1) change(1,y,z); else if(x==2) { ans=0; search(1,y,z); printf("%d\n",ans); } } return 0; }