def fun(): p = 120#int(input()) cnt=0 for i in range(3,int(p/3)): tmp = (p*(p-2*i))%(p-i) if tmp==0: j=(p*(p-2*i)/(p-i))/2 k=p-i-j if k>j: cnt+=1 print(cnt) fun()
The number given perimeter p, find all satisfy a + b + c = p and right triangle: Huawei written questions
Thinking: given a first side, in 3 ~ p / 3, and according to c = pac, a ^ 2 + b ^ 2 = c ^ 2, simplifying obtain b = (p * (p-2 * a)) / (pa) / 2; when b is a positive integer, satisfying,