python according to year, month information shows number of days this month

1  # conventional method 
2 year = int (INPUT ( ' Enter year: ' ))
 . 3 month The int = (INPUT ( ' Enter the month (1 ~ 12 is): ' ))
 . 4  IF month The == 2 :
 . 5      IF year% == 0. 4 and year 0 = 100%! or year 400% == 0:
 . 6          Print ( ' leap year 29 days ' )
 . 7      the else :
 . 8          Print ( ' average year 28 days ' )
 . 9  
10  elif month The in(4,6,9,11 ):
 . 11      Print ( " 30 days " )
 12 is  the else :
 13 is      Print ( ' 31 is days ' )

1  # Method two: function method 
2  DEF Y_M (year, month The):
 . 3      '' ' 
. 4      according to the year, month information shows number of days this month
 . 5      : param year: Enter Year:
 . 6      : param month The: Please enter the month (1 to 12 is):
 . 7      : return: the number of days
 . 8      '' ' 
. 9      IF month The> 12 is or month The <= 0:
 10          return -1
 . 11      IF month The == 2 :
 12 is          return 29 IF year. 4% 0 == and ! = 100% year 0 or year 400% == 0 the else 28
 13 is  
14     if month in (4, 6, 9, 11):
15         return 30
16     else:
17         return 31
18 
19 print(y_m(2004,12))