km²
inline void calc_next () { // Calculation of a next array pattern string starts from a next [ 1 ] = 0 ; for ( int I = 2 , J = 0 ; I <= n-; ++ I) { the while (J> 0 ! && A [I] = A [+ J . 1 ]) = J Next [J]; IF (A [I] == A [+ J . 1 ]) J ++ ; Next [I] = J; } }
inline void calc_f() { // kmp b为主串 从1开始 for (int i = 1, j = 0; i <= m; ++ i) { while (j > 0 && (j == n || b[i] != a[j + 1])) j = next[j]; if (b[i] == a[j + 1]) j ++; f[i] = j; if (f[i] == n) {/* the first time */} } }
exkmp
// find a prefix on the longest common suffix b's, Next recording a longest common prefix each on its own suffix, ret recorded on a longest common prefix of suffix b void ExtendedKMP ( char * a, char * b , int M, int N, int * the Next, int * RET) { int I, J, K; for (J = 0 ; . 1 + J <M && A [J] == A [ . 1 + J]; ++ J); the Next [ . 1 ] = J; K = . 1 ; for (I = 2 ; I <M; ++ I) { int Len = k + Next[k], L = Next[i - k]; if (L < Len - i) { Next[i] = L; } else { for (j = max(0, Len - i); i + j < M && a[j] == a[i + j]; ++ j); Next[i] = j; k = i; } } for (j = 0; j < N && j < M && a[j] == b[j]; ++ j); ret[0] = j; k = 0; for (i = 1; i < N; ++ i) { int Len = k + ret[k], L = Next[i - k]; if (L < Len - i) { ret[i] = L; } else { for (j = max(0, Len - i); j < M && i + j < N && a[j] == b[i + j]; ++ j); ret[i] = j; k = i; } } }