PAT 1067 test code (20 points)

Portal

Ideas:

1. All of the input first character string stored up until the read #;

2. Analyzing the character string one by one, and accordingly output.

note:

1. The number of password is correct and did not want to end the program exceeds the limit;

2. behind colon spaces;

3. If the password is wrong and has reached the limit must first enter the number of output Wrong password: the user enters the wrong password, and then outputs Account locked.

Attach AC Code:

 

. 1 #include <the iostream>
 2 #include <The iomanip>
 . 3 #include <cstdio>
 . 4  the using  namespace STD;
 . 5  
. 6  String STR [ 1000 ]; // to keep the string entered 
. 7  
. 8  int main () {
 . 9      String S ;
 10      int n-, CNT = 0 ;
 . 11      CIN >> S;
 12 is      CIN >> n-;
 13 is      . CIN GET (); // read out carriage 
14      the while ( . 1 ) {
 15         String T;
 16          getline (CIN, T);
 . 17          STR [CNT ++] = T;
 18 is          IF (T == " # " ) BREAK ;   // read # ends 
. 19      }
 20 is      for ( int I = 0 ; I < the CNT- . 1 ; I ++) {   // cycle # up to the front end of a string 
21 is          IF (STR [I] == S) {
 22 is              COUT << " available for purchase in " << endl;   // correct password and end 
23 is              BREAK ;
 24          }
25          the else COUT << " Wrong password: " << STR [I] << endl;
 26 is          IF (I == N- . 1 ) {     // If the limit number of times arrives at the input, output and Account locked ends 
27              COUT << " the Account Locked " ;
 28              BREAK ;
 29          }
 30      }
 31 is      return  0 ;
 32 } 

 

ACM white, there are many inadequacies, please correct me.

 

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Origin www.cnblogs.com/anitena/p/11347334.html