void Floyd(){
for(int k = 1; k <= n; ++k) {
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= n; ++j) {
dis[i][j] = min(dis[i][j], dis[i][k] + dis[k][j]);
}
}
}
}
This means that the use of k as a transit point to try to get a new detour the shortest distance between two points from k.
It uses only k of them, you can get without going through other points of the shortest effect. Hungary looks a bit feeling algorithm?
https://www.luogu.org/problem/P1119
Point k is added chronologically, shortest update.
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int MAXN = 205;
int n, m, t[MAXN];
int dis[MAXN][MAXN];
const int INF = 0x3f3f3f3f;
int main() {
#ifdef Yinku
freopen("Yinku.in", "r", stdin);
#endif // Yinku
scanf("%d%d", &n, &m);
for(int i = 1; i <= n; ++i)
for(int j = 1; j <= n; ++j)
dis[i][j] = INF;
for(int i = 1; i <= n; ++i)
dis[i][i] = 0;
for(int i = 1; i <= n; ++i)
scanf("%d", &t[i]);
for(int i = 1; i <= m; ++i) {
int u, v, w;
scanf("%d%d%d", &u, &v, &w);
++u,++v;
dis[u][v] = w;
dis[v][u] = w;
}
int q;
scanf("%d", &q);
int curti = 1;
while(q--) {
int u, v, T;
scanf("%d%d%d", &u, &v, &T);
++u,++v;
while(curti <= n && t[curti] <= T) {
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= n; ++j) {
dis[i][j] = min(dis[i][j], dis[i][curti] + dis[curti][j]);
}
}
++curti;
}
if(t[u] > T || t[v] > T)
puts("-1");
else
printf("%d\n", dis[u][v] < INF ? dis[u][v] : -1);
}
return 0;
}