62 hex 10 hex turn

C ++ implementation decimal turn hexadecimal

#include <stdio.h> 
#include <stdlib.h> 
#include < String >
 the using  namespace STD;
 // arbitrary characters are converted to decimal, where az represents 10-35, AZ representatives 36-61, with the corresponding ASCII code adjust like 
char i2char ( int n-) 
{ 
    IF (n-> = 0 && n-<= . 9 ) return  ' 0 ' + n-;
     IF (n-> = 10 && n-<= 35 ) return  ' A ' + (N- 10 );
     the else  return  ' A '+(n-36);
}
template<typename T> string num2str62(T& n)
{
    char buf[1024]={0};
    int index=0;
    while(n>0)
    {
        int m=n%62;
        n-=m;
        n/=62;
        buf[index++]=i2char(m);
    }
    string str=buf;
    string str2=string(str.rbegin(),str.rend());
    return str2;
}
int main(int narg,char** args)
{
    int n=10245;
    
    printf("%s\n",num2str62(n).c_str());
    return 0;

};