Android devices get a unique code

String uuid = "";
        String serial = null;

        String m_szDevIDShort = "35" +
                Build.BOARD.length() % 10 + Build.BRAND.length() % 10 +

                Build.CPU_ABI.length() % 10 + Build.DEVICE.length() % 10 +

                Build.DISPLAY.length() % 10 + Build.HOST.length() % 10 +

                Build.ID.length() % 10 + Build.MANUFACTURER.length() % 10 +

                Build.MODEL.length() % 10 + Build.PRODUCT.length() % 10 +

                Build.TAGS.length() % 10 + Build.TYPE.length() % 10 +

                Build.USER.length() % 10; // 13 

        the try { 
            serial . = Android.os.Build class .getField ( "the SERIAL") GET (. Null ) .toString ();
             // the API> Using the serial number. 9 = 
            UUID = new new the UUID (m_szDevIDShort.hashCode ( .), serial.hashCode ()) toString (); 
        } the catch (Exception Exception) {
             // Serial requires an initialization 
            Serial = "Serial"; // just one initialization
             // 15 bit number information is revealed to hardware 
            uuid = new new the UUID (m_szDevIDShort.hashCode (), serial.hashCode ()) toString ();. 
        }

Transfer: https://blog.csdn.net/u014031072/article/details/70257907