Dynamic Programming (DP) of the LIS / rise longest sequence

Description of the problem: Given a number of columns of length K A, up to find the value of a monotonically increasing sequence length is. Any sub-sequence B A can be expressed as B = {Ak1, Ak2, ...}, where k1 <k2 <....

State means: b [i] represents the length of A [i] is the end of the "rise longest sequence" of

Phasing: the end position of the sub sequence (position A in series, front to back)

Transfer equation: b [i] = max {b [j] +1} (0≤j <i, A [j] <A [i])

Border: b [0] = 0

Target: max {b [i]} 1≤i≤N

Code:

#include<bits/stdc++.h>
using namespace std;
int k;
int a[11011];
int b[11011];
int ans;
int main(){
	cin>>k;
	for(int i=1;i<=k;i++){
		cin>>a[i];
	}
	for(int i=1;i<=k;i++){
		for(int j=1;j<i;j++){
			if(a[i]>a[j]){
				b[i]=max(b[i],b[j]);
			}
		}
		b[i]++;
		ans=max(ans,b[i]);
	}
	cout<<ans<<endl;
	return 0;
}

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Origin www.cnblogs.com/hazel-wu/p/11294760.html