Title Description
Known: of Sn =. 1. 1 + / 2 +. 1 /. 3. 1 + ... + / n- . Clearly for any integer K , when n is large enough, of Sn is greater than K .
Are now given an integer K ( 1≤k≤15 ), requires a minimum of the calculated n- ; that of Sn> K .
Input Format
A positive integer K
Output Format
A positive integer N
Sample input and output
Input # 1
1
Output # 1
2
1 #include<bits/stdc++.h> 2 using namespace std; 3 int main() 4 { 5 int k,i=0; 6 double s=0.0000; 7 cin>>k; 8 do 9 { 10 i++; 11 s=s+ (1.0/i); 12 } while (s<=k); 13 cout<<i; 14 return 0; 15 }