A bug JavaScript floating-point operations.
For example: 7 * 0.8 JavaScript is calculated: 5.6000000000000005
// Call: numberExcept (arg1, arg2)
// Return Value: arg1 arg2 exact result of dividing
function numberExcept (arg1, arg2) {
var t1=0,t2=0,r1,r2;
try{t1=arg1.toString().split(".")[1].length}catch(e){}
try{t2=arg2.toString().split(".")[1].length}catch(e){}
with(Math){
r1=Number(arg1.toString().replace(".",""))
r2=Number(arg2.toString().replace(".",""))
return (r1/r2)*pow(10,t2-t1);
}
}
//transfer:
// Return Value: accurate results arg1 arg2 multiplying the
function numberRide (arg1, arg2)
{
var m=0,s1=arg1.toString(),s2=arg2.toString();
try{m+=s1.split(".")[1].length}catch(e){}
try{m+=s2.split(".")[1].length}catch(e){}
return Number(s1.replace(".",""))*Number(s2.replace(".",""))/Math.pow(10,m)
}
// Call: accAdd (arg1, arg2)
// Return Value: arg1 arg2 accurate results of adding
function accAdd (arg1, arg2) {
var R1, R2, m;
. Arg1.toString the try {R1 = () Split ( " . ") [. 1]} .length the catch (E) R1 = {0}
the try {arg2.toString R2 = (). Split (". ") [. 1]} .length the catch (E) R2 = {0}
m Math.pow = (10, Math.max (R1, R2))
return (arg1 arg2 * * m + m) / m
}
Subtraction function
function accSub(arg1, arg2) {
var r1, r2, m, n;
try { r1 = arg1.toString().split(".")[1].length } catch (e) { r1 = 0 }
try { r2 = arg2.toString().split(".")[1].length } catch (e) { r2 = 0 }
m = Math.pow(10, Math.max(r1, r2));
//last modify by deeka
//动态控制精度长度
n = (r1 >= r2) ? r1 : r2;
return ((arg1 * m - arg2 * m) / m).toFixed(n);
}