Computation - A / B Problem

• topic
• Code
• Explanation
• to sum up

topic:

A/B Problem

 

Write a program which reads two integers a and b, and calculates the following values:

 

• A ÷ B : D (in Integer) // find integer division
• of REMAINDER A ÷ B : R & lt (in Integer) // division remainder
• A ÷ B : F (in Real Number) // division result five significant digits reserved

 

Code:

#include<iostream>
#include<stdio.h>
using namespace std;
int main()
{
  int a,b;
  cin >> a >> b;
  double fa = a, fb = b;
  printf("%d %d %.5f\n",(a/b),(a%b),(fa/fb));
  return 0;
}

Explanation:

　　The entire C language library in C ++ primarily because precision is more complicated character on the introduction of the C language would be a lot easier. A / B is the integer part of the division request, A% B seek a remainder portion of the rear division, but relates to the fractional part or the need to convert to a double mode, in calculations.

 

to sum up:

　　Involving decimal calculations, the decimal point digit reference C language library, character conversion accuracy.