Procedure 2 [2] outputs prime number
Title: How many prime numbers between 101-200 judgment, and outputs all primes.
Program Analysis: Analyzing Method primes: 2, respectively, with the removal of a number sqrt (this number), if divisible, this indicates that the number is not prime, a prime number and vice versa.
package cskaoyan; import org.junit.Test; public class cskaoyan2 { @Test public void prime() { int min = 101; int max = 200; int count = 0; for (int i = min; i <= max; i++) { if (isPrime(i)) { count++; System.out.println(i); } } System.out.println(min + "-" + max + "之间有" + count + "个素数"); } public boolean isPrime(int number) { boolean flag = true; if (number < 2) { flag = false; } else if (number == 2) { flag = true; } else { for (int i = 2; i <= Math.sqrt(number); i++) { if (number % i == 0) { flag = false; break; } } } return flag; } }