Java parameter is always passed by value

Java parameter is always passed by value.

public class Main {
    public static void main(String[] args) {
        int x = 5;
        change(x);
        System.out.println(x);
    }

    public static void change(int x) {
        x = 10;
    }
}

5

public class Main {
    public static void swap(Integer i, Integer j) {
        Integer temp = new Integer(i);
        i = j;
        j = temp;
    }

    public static void main(String[] args) {
        Integer i = new Integer(10);
        Integer j = new Integer(20);
        swap(i, j);
        System.out.println("i = " + i + ", j = " + j);
    }
}

i = 10, j = 20

class Test {
    int x;

    Test(int i) {
        x = i;
    }

    Test() {
        x = 0;
    }
}

public class Main {
    public static void main(String[] args) {
        Test t = new Test(5);
        change(t);
        System.out.println(t.x);
    }

    public static void change(Test t) {
        t = new Test();
        t.x = 10;
    }
}

5

class Test {
    int x;

    Test(int i) {
        x = i;
    }

    Test() {
        x = 0;
    }
}

public class Main {
    public static void main(String[] args) {
        Test t = new Test(5);
        change(t);
        System.out.println(t.x);
    }

    public static void change(Test t) {
        t.x = 10;
    }
}

10