leetcode-922 odd and even sorted array II
Subject description:
Given a non-negative integer array A, the A half of the integer is an odd number, an even number of half integer. Sort the array, such that when A [i] is an odd number, I is an odd number; when A [i] is an even number, I is an even number.
Solution one:
class Solution:
def sortArrayByParityII(self, A: List[int]) -> List[int]:
i,j = 0,0
n = len(A)
indx = 0
while i < n and j<n:
while j<n and A[j]%2 == 1:
j += 1
while i < n and A[i]%2 == 0:
i += 1
if indx % 2 == 0:
A[indx],A[j] = A[j], A[indx]
indx += 1
j += 1
else:
A[indx],A[i] = A[i], A[indx]
indx += 1
i += 1
return A