Use simple file upload flask

Import the Flask Flask from, the redirect, the render_template, Request, the url_for 
from werkzeug.utils Import secure_filename 
Import OS 
App = the Flask (__ name__) 
ALLOWED_EXTENSIONS = SET ([ 'TXT', 'PDF', 'PNG', 'JPG', 'JPEG' , 'GIF', 'DOC']) 

# setting allows file uploads type 


DEF allowed_file (filename): 
    "" " 
    file type uploaded 
    : param filename: incoming file name 
    : return: return True or False 
    " "" 
    filename.rsplit filename and in return (,. 1 ".") [. 1] in ALLOWED_EXTENSIONS. "" 


@ app.route ( "/", Methods = [ "the GET", "the POST"]) 
DEF file_name (): 
    "" " 
    Upload file 
    : return:Return to the upload file url address 
    "" " 
    IF request.method ==" POST ": 
        f = request.FILES [" File "]
        if f and allowed_file(f.filename):
            path = os.path.split(os.getcwd())[0]
            print(path)
            file = path+"/demo/templates/"+secure_filename(f.filename)
            print(file)
            f.save(file)
            return redirect("/uploads")
        else:
            return redirect(url_for("fail"))
    return render_template("file_name.html")


@app.route("/uploads")
def successful():
    """
    设置返回路径的视图函数
    :return:
    """
    url = url_for("file_name")
    return '访问文件的路径：http://127.0.0.1:5000{}'.format(url)


@app.route("/fail")
def fail():
    """
    The view function of the file type does not match 
    : return: 
    "" " 
    return" file does not conform to the rules " 


IF the __name__ == '__main__': 
    app.run (Debug = True)