Java brute-force method to find a poker inside in addition to the king size add up to 24 points of all possible

| - demand explanation

Find a poker other than a king size for each card only out of one, obtained by adding all of the possible 24 points

 

| - problem-solving ideas

 

 

| - Content Code

. 1  / ** 
2  * 9527 :: @auther
 . 3  * @Description:
 . 4  * @program: Port
 . 5  * @Create: 2019-07-17 16:58
 . 6   * / 
. 7  public  class Equail24 {
 . 8      public  static  void main (String [] args) {
 . 9          Double SUM = 0;      // record the total number of 
10          Double COUNT = 0;   // record the number of times become 24 points 
. 11          Double probability;   // calculate the probability of
 12          @ represents the variable i by hearts card number 
13          for ( int. 1 = I; I <= 13 is; I ++ ) {
 14              // number of cards to identify the variable j with the spade 
15              for ( int j =. 1; j <= 13 is; j ++ ) {
 16                  // to use this variable k the number of card identification blocks 
. 17                  for ( int K =. 1; K <= 13 is; K ++ ) {
 18 is                      // with l this variable to identify plum number of cards 
. 19                      for ( int l =. 1; l <= 13 is; l ++ ) {
 20 is                          SUM = +. 1 ;
 21 is                          IF (I + J + K + L == 24 ) {
 22 is                              System.out.println ( "hearts" + I + "\ T" +
 23 is                                     "Spades" + J + "\ T" +
 24                                      "box" + K + "\ T" +
 25                                      "Plum" + l + "\ t" + " is the sum of 24 points" );
 26 is                              COUNT +. 1 = ;
 27                          }
 28  
29                      }
 30  
31 is                  }
 32  
33 is              }
 34 is  
35          }
 36          Probability = COUNT / SUM * 100 ;
 37 [          System.out.println ( "" );
 38 is         System.out.println ( "four kinds of cards, one each from each of Poker, a total of 4 13 = 28561 kinds of power arrangement method," +
 39                  "the total number of aligned points is 24" + count + "\ n the probability of 24 points is routed "probability + +"% " );
 40  
41 is      }
 42 is }

Exhaustive method, four, out of a poker each, routed the sum of all possible 24 points

 

 

| - operating results