View picture android network

Original link: http://www.cnblogs.com/heml/p/3511340.html

 

 

public class MainActivity extends Activity {
    private EditText pathText;
    private ImageView imageView;
    
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        
        pathText = (EditText) this.findViewById(R.id.imagepath);
        imageView = (ImageView) this.findViewById(R.id.imageView);
        Button button = (Button) this.findViewById(R.id.button);
        button.setOnClickListener(new ButtonClickListener());
    }
    
    private final class ButtonClickListener implements View.OnClickListener{

        public void onClick(View v) {
            String path = pathText.getText().toString();
            try{
                byte[] data = ImageService.getImage(path);
                Bitmap bitmap = BitmapFactory.decodeByteArray(data, 0, data.length);
                imageView.setImageBitmap(bitmap);//显示图片
            }catch (Exception e) {
                e.printStackTrace();
                Toast.makeText(getApplicationContext(), R.string.error, 1).show();
            }
        }
    }
}

 

public  class ImageService {
     / ** 
     * image data obtained network 
     * @param path network image path 
     * @return 
     * / 
    public  static  byte [] the getImage (String path) throws Exception { 
        the URL URL = new new the URL (path); 
        the HttpURLConnection Conn = (the HttpURLConnection) url.openConnection (); // HTTP-based protocol connection object 
        conn.setConnectTimeout (5000 ); 
        conn.setRequestMethod ( "the GET" );
         IF (conn.getResponseCode () == 200 is  ) {
            the InputStream inStream= conn.getInputStream();
            return StreamTool.read(inStream);
        }
        return null;
    }

}

public class StreamTool {
    /**
     * 读取流中的数据
     * @param inStream
     * @return
     * @throws Exception
     */
    public static byte[] read(InputStream inStream) throws Exception{
        ByteArrayOutputStream outStream = new ByteArrayOutputStream();
        byte[] buffer = new byte[1024];
        int len = 0;
        while( (len = inStream.read(buffer)) != -1){
            outStream.write(buffer, 0, len);
        }
        inStream.close();
        return outStream.toByteArray();
    }

}

If the web in the machine, and can not be tested with localhost 127.0.0.1, you can use the LAN ip.

 

 

 

 

 

Reproduced in: https: //www.cnblogs.com/heml/p/3511340.html