Conditional statements and Pascal's Triangle

1.
5 athletes took part in the 10-meter platform diving competition, someone let them predict match results,
player A says: B second, my third;
B players said: I second, E IV;
C contestant said: I first , D second;
D players, said: C Finally, my third;
E contestant said: I IV, a first;
after the game, each player say half right, please programmed to determine the ranking of the game.

#include<stdio.h>
#include<stdlib.h>

int main()
{
	int a, b, c, d, e;
	for (a = 1; a <= 5; ++a)
	{
		for (b = 1; b <= 5; ++b)
		{
			for (c = 1; c <= 5; ++c)
			{
				for (d = 1; d <= 5; ++d)
				{
					for (e = 1; e <= 5; ++e)
					{
						if (a*b*c*d*e == 120)
						{
							if(((b == 2) + ( a == 3) == 1) &&
							((b == 2) + (e == 4)== 1) &&
							((c == 1) + (d == 2) == 1) &&
							((c == 5) + (d == 3) == 1) &&
							((e == 4) + (a == 1) == 1))
							{
								printf("a = %d, b = %d, c = %d, d = %d, e = %d", a, b, c, d, e);
							}
						}
						
					}
				}
			}
		}
	}
	printf("\n");
	system("pause");
	return 0;
}

2.
Japan somewhere there have been a murder, the police through the investigation to determine the murderer will be for 4
a suspects. The following is the four suspects confession.
A said: not me.
B said: It is C.
C said: It is D.
D said: C nonsense
known three people told the truth, one person was lying.
Based on this information now, please, write a program to determine in the end who is the murderer.

#include<stdio.h>
#include<stdlib.h>

int main()
{
	int killer = 0;
	for (killer = 'A'; killer <= 'D'; ++killer)
	{
		if ((killer != 'A') + (killer == 'C') + (killer == 'D') + (killer != 'D') == 3)
		{
			printf("killer is %c\n", killer);
		}
	}
	system("pause");
	return 0;
}

3. Pascal's Triangle print on the screen.
. 1
. 1. 1
. 1 2. 1
. 1. 1. 3. 3

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
#define N 10

int main()
{
	int array[N][N] = { 0 };
	int i = 0;
	int j = 0;
	int k = 0;
	for (i = 0; i < N; i++)
	{
		array[i][1] = 1;
		array[i][j] = 1;
	}
	for (i = 2; i < N; ++i)
	{
		for (j = 1; j < 10; ++j)
		{
			array[i][j] = array[i - 1][j] + array[i - 1][j - 1];
		}
	}
	for (i = 0; i < N; ++i)
	{
		
		for (j = 0; j <= i; ++j)
		{
			printf("%d  ", array[i][j]);
		}
		for (k = 0; k < N - i; ++k)
		{
			printf(" ");
		}
		printf("\n");
	}
	system("pause");
	return 0;
}