Mall - registered user - user name and password based on user queries

The user name and password to query the user

7.1. Interface Description

Function Description

Queries, query the user according to the parameters specified in the user name and password

Interface path

GET /query

Parameter Description:

form Form format

parameter	Explanation	Do you have to	type of data	Defaults
username	User name in the form of 4 to 30 letters, numbers, underscores	Yes	String	no
password	User password, the format of 4 to 30 letters, numbers, underscores	Yes	String	no

Return result:

User data format json

{
    "id": 6572312,
    "username":"test",
    "phone":"13688886666",
    "created": 1342432424
}

status code:

• 200: Registration successful
• 400: The user name or password is incorrect
• 500: Internal Server exceptions, failed to register

7.2.controller

/**
 * 根据用户名和密码查询用户
 * @param username
 * @param password
 * @return
 */
@GetMapping("query")
public ResponseEntity<User> queryUser(
    @RequestParam("username") String username,
    @RequestParam("password") String password
    ) {
        User user = this.userService.queryUser(username, password);
        if (user == null) {
            return ResponseEntity.status(HttpStatus.BAD_REQUEST).build();
        }
        return ResponseEntity.ok(user);
    }

7.3.service

public User queryUser(String username, String password) {
    // 查询
    User record = new User();
    record.setUsername(username);
    User user = this.userMapper.selectOne(record);
    // 校验用户名
    if (user == null) {
        return null;
    }
    // 校验密码
    if (!user.getPassword().equals(CodecUtils.md5Hex(password, user.getSalt()))) {
        return null;
    }
    // 用户名密码都正确
    return user;
}

Note that after the password encryption should determine whether the same query.

7.4. Test

We RestClient test:

8. Test at the registration page

Fill in the information in the registration page:

Submit discover page automatically jump to the login page, check the database: