Write a program to count all integers from 1 to 100 occurrences 9
c language:
the X-single-digit integer represents 10% of
x / 10% 10 represents an integer of tens
x / 100 represents one hundred and so on ...
#include <stdio.h>
#include <stdlib.h>
int main() {
int i=0, m=0;
for (i = 1; i <= 100; i++) {
if (i%10==9) {
m++;
}
if (i/10 == 9) {
m++;
}
}
printf("出现9的次数为:%d\n", m);
system("pause");
return 0;
}