table of Contents
Subject description:
You need to find the maximum value in each row of the binary tree.
Example:
输入:
1
/ \
3 2
/ \ \
5 3 9
输出: [1, 3, 9]
solution:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> largestValues(TreeNode* root) {
vector<TreeNode*> cur(1, root);
vector<TreeNode*> nxt;
if(root == NULL){
return {};
}else{
vector<int> res;
while(!cur.empty()){
nxt.clear();
int val = INT_MIN;
for(TreeNode* node : cur){
val = max(val, node->val);
if(node->left){
nxt.push_back(node->left);
}
if(node->right){
nxt.push_back(node->right);
}
}
res.push_back(val);
cur = nxt;
}
return res;
}
}
};