65. The algorithm is simple and swift ransom letter

Given a ransom channel (ransom) and a string magazine (magazine) string, the first string is determined ransom can consists of a second character string inside the magazines. If you can constitute, return true; otherwise false.

(Title Description: In order not to expose ransom letter writing, from the search needs of each magazine letters to form words to express the meaning.)

note:

You can assume two strings contain only lowercase letters.

canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true

solution:

    func canConstruct(_ ransomNote: String, _ magazine: String) -> Bool {
         if ransomNote.count > 0 && magazine.count > 0 {
            
        }else if ransomNote.count == 0 && magazine.count == 0 {
            return true
        }else if ransomNote.count == 0 && magazine.count > 0{
            return true
        }else{
            return false
        }
      
        var magazine = magazine
       
        for item in ransomNote {
            if let index = magazine.firstIndex(of: item) {
                magazine.remove(at: index)
            }else{
                return false
            }
        }
        
        
        return true
    }