Requirements: A total of five stores, one by shopping, buy goods commodity information is printed, the amount of each purchase record. Walk around five shops give the total amount of output
Analysis: a cycle visiting five shops, small cycles asked whether the purchase of goods, buying every time, commodity prices accumulation.
#!/bin/bash
# Commodity price print function
info() {
printf " Price list
1、hat 50￥
2、shoes 200￥
3、clothes 300￥
4、trousers 100￥
5、glove 30￥
"
}
# Commodity selection small cycles, and cumulative price.
shopping() {
if [ $act == "y" ];then
read -p "Please choose the goods.(1-5): " buy
case $buy in
1)
# ++ array index used here, with the final price index corresponding value *
# Is equivalent to let hatsum = $ [hatsum + 50]
let hat[1]++
Hatsum = $ [$ {has [1]} * 50]
echo "You spent ${hatsum}￥ on the hat"
;;
2)
let shoes[2]++
shoessum=$[${shoes[2]} * 200 ]
echo "You spent ${shoessum}￥ on the shoes"
;;
3)
let clothes[3]++
clothessum=$[${clothes[3]} * 300 ]
echo "You spent ${clothessum}￥ on the clothes"
;;
4)
let tro[4]++
trosum = $ [$ {believe [4]} * 100]
echo "You spent ${trosum}￥ on the trosum"
;;
5)
let glove[5]++
glovesum=$[${glove[5]} * 30 ]
echo "You spent ${glovesum}￥ on the glove"
;;
*)
echo "please enter number 1-5......"
;;
esac
else
break
be
}
# 5 visiting a cycle store, if the implementation of small cycles, n to y, or others continue, skip this cycle. Where a determination is not strict, will not skip this cycle n.
for i in `seq 5`
do
read -p "Pass the $i store,Go in and have a look?(y/n): " cho
if [ "$cho" = "y" ];then
while :
do
info
read -p "Do you want to buy anything?(y/n): " act
shopping
done
else
continue
be
done