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a = 2
for i in range(10):
print('原来的i {0}'.format(i))
if a < 3:
i -= 1
print('后面的i {0}'.format(i))
原来的i 0
后面的i -1
原来的i 1
后面的i 0
原来的i 2
后面的i 1
原来的i 3
后面的i 2
原来的i 4
后面的i 3
原来的i 5
后面的i 4
原来的i 6
后面的i 5
原来的i 7
后面的i 6
原来的i 8
后面的i 7
原来的i 9
后面的i 8
When we use the present cycle except + skip and return cycle, the cycle parameters may be modified i- = 1, but using range () does not produce modified for cycle i the cycle, into use for i <n: such cycles can be.
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