Topic links: https://leetcode-cn.com/problems/binary-tree-inorder-traversal/
Title Description
Given a binary tree in preorder to return it.
示例:
输入: [1,null,2,3]
1
\
2
/
3
输出: [1,3,2]
Advanced: recursive algorithm is very simple, you can do it through an iterative algorithm?
Thinking
Non-recursive
Stack storage is not accessible right child
class Solution {
public:
vector<int> inorderTraversal(TreeNode* root) {
vector<int> ret;
if(!root) return ret;
stack<TreeNode *> s;
TreeNode *last = nullptr;
while (root || !s.empty()){
while (root){
s.push(root);
root = root->left;
}
if(!s.empty()){
root = s.top();
s.pop();
ret.push_back(root->val);
root = root->right;
}
}
return ret;
}
};