To prove safety Offer 66

 1 # -*- coding:utf-8 -*-
 2 class Solution:
 3     def multiply(self, A):
 4         n = len(A)
 5         mat = [[1 for _ in range(n)]for _ in range(n)]
 6         for i in range(n):
 7             for j in range(n):
 8                 if i != j:
 9                     mat[i][j] = A[j]
10         B = [1] * n
11         for i in range(n):
12             mul = 1
13             for j in range(n):
14                 mul *= mat[i][j]
15             B[i] = mul
16         return B
17         # write code here