English title
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
For example, this binary tree [1,2,2,3,4,4,3] is symmetric:
1
/ \
2 2
/ \ / \
3 4 4 3
But the following [1,2,2,null,3,null,3] is not:
1
/ \
2 2
\ \
3 3
Chinese title
Given a binary tree, check if it is mirror-symmetrical.
For example, a binary tree [1,2,2,3,4,4,3]is symmetrical.
1
/ \
2 2
/ \ / \
3 4 4 3
However, the following [1,2,2,null,3,null,3]is not a mirror image:
1
/ \
2 2
\ \
3 3
Algorithm
/**
* Definition for a binary tree node.
* public class TreeNode {
* public int val;
* public TreeNode left;
* public TreeNode right;
* public TreeNode(int x) { val = x; }
* }
*/
//镜像对称的递归函数
public bool IsMirror(TreeNode t1, TreeNode t2)
{
if (t1 == null && t2 == null) return true;
if (t1 == null || t2 == null) return false;
return (t1.val == t2.val)
&& IsMirror(t1.left, t2.right)
&& IsMirror(t1.right, t2.left);
}
Experimental results
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Reproduced in: https: //www.jianshu.com/p/4e8e0301d402