HDUOJ2031: hex conversion

Copyright: qq836678589 https://blog.csdn.net/weixin_43924623/article/details/90521512

Hexadecimal conversion

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 73111 Accepted Submission(s): 39670

Problem Description
input a decimal number N, it converts into R decimal output.

Input
input data comprising a plurality of test cases, each test case contains two integers N (32-bit integer) and R (2 <= R <= 16, R <> 10).

Output
number after each test case conversion output, each output per line. If rule number R is greater than 10, then the corresponding hexadecimal reference (for example, represented by 10 A, etc.).

Sample Input
7 2
23 12
-4 3

Sample Output
111
1B
-11

#include<iostream>
using namespace std;
int main(){
	int n,r,num[100],i;
	bool a;
	while(cin>>n>>r){
		i=0;
		a=false;
		if(n<0){
			a=true;
			n=-n;
		}
		while(n){
			num[i++]=n%r;
			n=n/r;
		}
		if(a){
			cout<<"-";
		}
		for(int j=i-1;j>=0;j--){
			if(num[j]<10)
			cout<<num[j];
			else
			printf("%c",num[j]+55);
		}
		cout<<endl;
	}
	return 0;
}