Given three strings s1, s2, s3, s3 verify interleaved by s1 and s2 thereof.
Example 1:
Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbcbcac"
Output: true
Example 2:
Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbbaccc"
Output: false
bool isInterleave(char * s1, char * s2, char * s3){
int len1=strlen(s1);
int len2=strlen(s2);
int len3=strlen(s3);
if(len1+len2!=len3)return false;
bool ** state=(bool **)malloc(sizeof(bool *)*(len2+1));
for(int i=0;i<len2+1;i++)
{
state[i]=(bool *)calloc(len1+1,sizeof(bool));
}
state[0][0]=true;
for(int i=1;i<=len2;i++)
{
state[i][0]=state[i-1][0]&&s2[i-1]==s3[i-1];
}
for(int i=1;i<=len1;i++)
{
state[0][i]=state[0][i-1]&&s1[i-1]==s3[i-1];
}
for(int i=1;i<=len2;i++)
{
for(int j=1;j<=len1;j++)
{
state[i][j]=(state[i-1][j]&&s2[i-1]==s3[i+j-1])||(state[i][j-1]&&s1[j-1]==s3[i+j-1]);
}
}
bool ret=state[len2][len1];
for(int i=0;i<len2+1;i++)
{
free(state[i]);
}
free(state);
return ret;
}When execution: 8 ms, beat the 85.71% of users Interleaving String submission of C
Memory consumption: 7.1 MB, defeated 12.50% of users Interleaving String submission of C