B. Nauuo and Chess

Links: https://codeforces.com/contest/1173/problem/B

Meaning of the questions:

Nauuo is a girl who loves playing chess.

One day she invented a game by herself which needs nn chess pieces to play on a m×mm×mchessboard. The rows and columns are numbered from 11 to mm. We denote a cell on the intersection of the rr-th row and cc-th column as (r,c)(r,c).

The game's goal is to place nn chess pieces numbered from 11 to nn on the chessboard, the ii-th piece lies on (ri,ci)(ri,ci), while the following rule is satisfied: for all pairs of pieces ii and jj, |ri−rj|+|ci−cj|≥|i−j||ri−rj|+|ci−cj|≥|i−j|. Here |x||x| means the absolute value of xx.

However, Nauuo discovered that sometimes she couldn't find a solution because the chessboard was too small.

She wants to find the smallest chessboard on which she can put nn pieces according to the rules.

She also wonders how to place the pieces on such a chessboard. Can you help her?

Ideas:

X * x matrix structure of the upper left corner to put 1, bottom right corner to put n,

Since (nx) = (nx)

Therefore, the first row of the matrix to fill 1-x, the last line is filled from right to left n- (x + 1).

Code:

#include <bits/stdc++.h>

using namespace std;

typedef long long LL;
const int MAXN = 1e3 + 10;
const int MOD = 1e9 + 7;
int n, m, k, t;
int x, y;

int A[MAXN][MAXN];

int main ()
{
    cin >> n;
    if (n == 1)
    {
        cout << 1 << endl;
        cout << 1 << ' ' << 1 << endl;
        return 0;
    }
    for (int i = 2;i <= n;i++)
        if ((i-1)*2 >= n-1)
        {
            x = y = i;
            break;
        }
    for (int i = 1;i <= x;i++)
        A[1][i] = i;
    for (int i = x, v = n;i >= 1 && v > x;i--,v--)
        A[x][i] = v;

    cout << x << endl;
    for (int i = 1;i <= x;i++)
        for (int j = 1;j <= y;j++)
            if (A[i][j] <= n && A[i][j] >= 1)
                cout << i << ' ' << j << endl;

    return 0;
}