BIG # 3094. 「BJOI2019」 删 数
Do atcoder done it this conclusion before I forget the result. . .
EM, it is the \ ([1, n] \ ) for each number between \ (I \) , then \ ([i - cnt [i ] + 1, i] \) can put a segment, the segment has not been put where is the need to change the sum of the number of
After we segment tree maintenance intervals and the minimum number of
We should note that such a +1 if the original in \ ([1, N] \ ) point beyond the range, it is imperative to delete this range, -1 Similarly, to add to the mix
Range open into \ (N + 2M \) is \ (4.5 * 10 ^ 5 {} \) to
#include <bits/stdc++.h>
#define fi first
#define se second
#define pii pair<int,int>
#define mp make_pair
#define pb push_back
#define space putchar(' ')
#define enter putchar('\n')
#define eps 1e-10
#define MAXN 500005
#define ba 47
//#define ivorysi
using namespace std;
typedef long long int64;
typedef unsigned int u32;
typedef double db;
template<class T>
void read(T &res) {
res = 0;T f = 1;char c = getchar();
while(c < '0' || c > '9') {
if(c == '-') f = -1;
c = getchar();
}
while(c >= '0' && c <= '9') {
res = res * 10 +c - '0';
c = getchar();
}
res *= f;
}
template<class T>
void out(T x) {
if(x < 0) {x = -x;putchar('-');}
if(x >= 10) {
out(x / 10);
}
putchar('0' + x % 10);
}
const int MAXV = 150000,LEN = 450000;
int N,M;
int a[MAXN],d;
int cnt[LEN + 5];
int getpos(int x) {
return x - d + MAXV;
}
struct node {
int l,r,val,cnt,lz;
}tr[LEN * 4 + 5];
void update(int u) {
tr[u].val = min(tr[u << 1].val,tr[u << 1 | 1].val);
tr[u].cnt = 0;
if(tr[u].val == tr[u << 1].val) tr[u].cnt += tr[u << 1].cnt;
if(tr[u].val == tr[u << 1 | 1].val) tr[u].cnt += tr[u << 1 | 1].cnt;
}
void build(int u,int l,int r) {
tr[u].l = l;tr[u].r = r;
if(l == r) {tr[u].cnt = 1;return;}
int mid = (l + r) >> 1;
build(u << 1,l,mid);
build(u << 1 | 1,mid + 1,r);
update(u);
}
void addlz(int u,int v) {
tr[u].val += v;tr[u].lz += v;
}
void pushdown(int u) {
if(tr[u].lz) {
addlz(u << 1,tr[u].lz);
addlz(u << 1 | 1,tr[u].lz);
tr[u].lz = 0;
}
}
void add(int u,int l,int r,int v) {
if(tr[u].l == l && tr[u].r == r) {
addlz(u,v);
return;
}
pushdown(u);
int mid = (tr[u].l + tr[u].r) >> 1;
if(r <= mid) add(u << 1,l,r,v);
else if(l > mid) add(u << 1 | 1,l,r,v);
else {add(u << 1,l,mid,v);add(u << 1 | 1,mid + 1,r,v);}
update(u);
}
pii Query(int u,int l,int r) {
if(tr[u].l == l && tr[u].r == r) return mp(tr[u].val,tr[u].cnt);
pushdown(u);
int mid = (tr[u].l + tr[u].r) >> 1;
if(r <= mid) return Query(u << 1,l,r);
else if(l > mid) return Query(u << 1 | 1,l,r);
else {
pii a = Query(u << 1,l,mid),b = Query(u << 1 | 1,mid + 1,r);
if(a.fi > b.fi) swap(a,b);
if(a.fi == b.fi) a.se += b.se;
return a;
}
}
void Solve() {
read(N);read(M);
build(1,1,LEN);
for(int i = 1 ; i <= N ; ++i) {
read(a[i]);
a[i] += MAXV;
add(1,a[i] - cnt[a[i]],a[i] - cnt[a[i]],1);
cnt[a[i]]++;
}
int p,x;
for(int i = 1 ; i <= M ; ++i) {
read(p);read(x);
if(p == 0) {
if(x == 1) {
if(cnt[getpos(N)]) {add(1,getpos(N) - cnt[getpos(N)] + 1,getpos(N),-1);}
}
else {
if(cnt[getpos(N + 1)]) {add(1,getpos(N + 1) - cnt[getpos(N + 1)] + 1,getpos(N + 1),1);}
}
d += x;
}
else {
if(a[p] <= getpos(N)) {
add(1,a[p] - cnt[a[p]] + 1,a[p] - cnt[a[p]] + 1,-1);
}
cnt[a[p]]--;
a[p] = x - d + MAXV;
if(a[p] <= getpos(N)) {
add(1,a[p] - cnt[a[p]],a[p] - cnt[a[p]],1);
}
cnt[a[p]]++;
}
pii res = Query(1,getpos(1),getpos(N));
int ans = 0;
if(res.fi == 0) ans = res.se;
out(ans);enter;
}
}
int main() {
#ifdef ivorysi
freopen("f1.in","r",stdin);
#endif
Solve();
}