B has n small bulb closed, numbered 1 ... n.
B n-th wheel will be small operation, the i-th round she will numbered multiple of the switching status of the lamp i negated, i.e., turned-open, closed into open.
After the n-th wheel required operation, how much the bulb is on.
Entry
A lamp input number indicates the number of n, where 1 <n≤10000000
Export
A number indicates the final output of the lamp lit
SAMPLE INPUT
3
Sample Output
1
water. .
Code:
#include <iostream> #include <cstdlib> #include <cstdio> #include <cmath> using namespace std; int main() { int n; scanf("%d",&n); printf("%d",int(sqrt(n))); return 0; }