Level 4: Structure stores student information

mission details

The task of this level: Use a structure to store student information (including student ID, name, grades of 3 courses, and total score). It is required to modify and delete student information, up to 50 students.

related information

Reference knowledge related to structure level 1

Programming requirements

Add code in the Begin-End section of the editor on the right , use structures to store student information, and modify and delete student information.

Test instruction

The platform will test the code you write and compare the values ​​you output with the actual correct values. Only when all data are calculated correctly can the test pass:

Test input:

10 3
1 Siyu 90 90 90
2 Amy 60 70 94
3 Jack 60 60 98
4 Jack 77 90 60
5 Banana 60 60 40
6 White 60 60 60
7 Pinkman 60 60 60
8 Fring 60 60 70
9 Ehrmantraut 80 63 61
10 Schrader 99 66 100
1 Jack
2 1 100 100 100
3 10

Test input data description: Enter n and q . The n lines below the bid document are the information of n students, and the next q lines are the corresponding operations.

1 name //为根据名字查询操作
2 sno num1 num2 num2 //为修改分数操作，修改学号为sno的3门成绩
3 sno //为删除操作

Expected output:

3 Jack 60 60 98 218
4 Jack 77 90 60 227
1 Siyu 100 100 100 300
2 Amy 60 70 94 224
3 Jack 60 60 98 218
4 Jack 77 90 60 227
5 Banana 60 60 40 160
6 White 60 60 60 180
7 Pinkman 60 60 60 180
8 Fring 60 60 70 190
9 Ehrmantraut 80 63 61 204
10 Schrader 99 66 100 265
1 Siyu 100 100 100 300
2 Amy 60 70 94 224
3 Jack 60 60 98 218
4 Jack 77 90 60 227
5 Banana 60 60 40 160
6 White 60 60 60 180
7 Pinkman 60 60 60 180
8 Fring 60 60 70 190
9 Ehrmantraut 80 63 61 204

Expected output data description: Each modification operation will output all student information, and a query operation will output the queried student information.

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Start your mission and wish you success!

#include<stdio.h>
#include<string.h>
int Count;
struct student {
    char sno[20], name[20];
    int math, english, chinese, sum;
};

void print(struct student stu) {
    printf("%s %s %d %d %d %d\n", stu.sno, stu.name, stu.math, stu.english, stu.chinese, stu.sum);
}

void query_stu(struct student s[], char* name) {
    /*********Begin*********/
    //遍历结构体数组，找到与name相同的学生，并打印其信息
    for (int i = 0; i < Count; i++) {
        if (strcmp(s[i].name, name) == 0) {
            print(s[i]);
        }
    }
    /*********End**********/
}

void delete_stu(struct student s[], char* sno) {
    /*********Begin*********/
    //遍历结构体数组，找到与sno相同的学生，并将其后面的元素依次向前移动一位
    for (int i = 0; i < Count; i++) {
        if (strcmp(s[i].sno, sno) == 0) {
            for (int j = i + 1; j < Count; j++) {
                s[j - 1] = s[j];
            }
            break;
        }
    }
    /*********End**********/
}

void update_stu(struct student s[], char* sno, int math, int english, int chinese) {
    /*********Begin*********/
    //遍历结构体数组，找到与sno相同的学生，并更新其成绩和总分
    for (int i = 0; i < Count; i++) {
        if (strcmp(s[i].sno, sno) == 0) {
            s[i].math = math;
            s[i].english = english;
            s[i].chinese = chinese;
            s[i].sum = math + english + chinese;
            break;
        }
    }
    /*********End**********/
}

int main(void)
{
    int n, q;
    struct student students[50];
    scanf("%d%d", &n, &q);
    Count = n;
    for (int i = 0; i < n; i++) {
        /*********Begin*********/
        //输入每个学生的信息，并计算总分
        scanf("%s%s%d%d%d", &students[i].sno,
            &students[i].name,
            &students[i].math,
            &students[i].english,
            &students[i].chinese);
        students[i].sum =
            students[i].math +
            students[i].english +
            students[i].chinese;
        /*********End**********/
    }
    while (q--) {
        int op;
        scanf("%d", &op);
        char sno[20], name[20];
        if (op == 1) {
            scanf("%s", name);
            query_stu(students, name);
        }
        else if (op == 2) {
            int a, b, c;
            scanf("%s%d%d%d", sno, &a, &b, &c);
            update_stu(students, sno, a, b, c);
            for (int i = 0; i < Count; i++)
                print(students[i]);
        }
        else {
            scanf("%s", sno);
            delete_stu(students, sno);
            for (int i = 0; i < Count - 1; i++)
                print(students[i]);
        }
    }
    return 0;
}