Assembly language subroutine for converting hexadecimal strings

The subroutine that implements hexadecimal string conversion in assembly language usually needs to process each character of the string and convert it into the corresponding numerical value. The following is a simple x86 assembly language subroutine example for converting a hexadecimal string to an integer:

section .data
    hex_string db "1A2F", 0 ; The hexadecimal string is null-terminated
    result dd 0 ; After storage conversion integer result

section .text
    global _start

_start:
    ; Pass the address of the hexadecimal string to the subroutine
    mov esi, hex_string

    call hex_to_int

    ; The result is stored in result, you can use it here
    ; ...

    ; Exit the program
    mov eax, 1 ; System call number 1 indicates exit
    xor ebx, ebx ; Return code is 0
    int 0x80 ; Call the kernel

hex_to_int:
    ; Input: esi points to hexadecimal string

    xor eax, eax ; Clear the eax register, used to store the result
    xor ecx, ecx ; Clear the ecx register, used for loop counting

convert_loop:
    movzx edx, byte [esi] ; Read a character in the string and extend it to 32 bits with 0
    cmp dl , 0           ; If the character is null, exit the loop
    je convert_done

    sub dl, '0' ; Convert characters to numbers
    cmp dl, 9 ; Check if it is a number between 0-9
    jbe numeric_digit

    sub dl, 'A' - 10 ; If it is not a number, check if it is a letter between A-F
    cmp dl, 5 ; ' The ASCII code difference of characters between A' and 'F' is 5
    jbe alpha_digit

    sub dl, 'a' - 10 ; If it is not a capital letter, check whether it is a lowercase letter between a-f
    cmp dl, 5
    jbe alpha_digit

    ; If it is not a valid hexadecimal character, you can handle the error here or exit directly

numeric_digit:
    imul eax, 16 ; Multiply the current result by 16
    add eax, edx ; Add the current number to the result
    jmp next_character

alpha_digit:
    imul eax, 16 ; Multiply the current result by 16
    add eax, edx ; Add the current number to the result
    add eax, 10 ; Since it is a letter, you need to add 10

next_character:
    inc esi ; Move to the next character in the string
    inc ecx ; Increment the loop count
    cmp ecx, 8 ; Assume the maximum length of the string is 8
    jne convert_loop ; Continue loop

convert_done:
    ret

Please note that this is just a simple example and may need to be adjusted based on actual needs. This code assumes that the length of the input hexadecimal string does not exceed 8 characters and is within a reasonable range. You may need to modify it to meet your needs.

 

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Origin blog.csdn.net/qq_50942093/article/details/134551084