Learn C++ from a young age! Record the questions in the learning process of Xueersi Monkey programming and record every moment. Any infringement will be deleted immediately, thank you for your support!
Attached is a summary post: Little Monkey Programming C++ | Summary-CSDN Blog
[Title description]
There is a row of street lights on a road of length L outside the gate of a school . The distance between every two adjacent lights is 1 meter. We can think of the road as a number axis. One end of the road is at the position of 0 on the number axis, and the other end is at the position of L. Each integer point on the number axis, that is, 0, 1, 2, ⋯, L has a street light, which is numbered sequentially. is 0∼L .
Pulling the switch of each light can change in the order of off-red-yellow-green-blue-off. Initially, all street lights are off. Now there are n action sequences, each marking the meaning of the current action and the starting and ending positions. The specific meaning of each action is as follows:
- 1 st: Turn all the lights between the s- th light to the t- th light (including the s -th light and the t- th light) into the off state;
- 2 st: Turn all the lights on between the s- th light and the t -th light (including the s- th light and the t -th light) into red or green, and stop when the light turns red or green. Pull the switch;
- 3 st: Turn all the lights between the s- th light and the t -th light (including the s- th light and the t -th light) into blue or yellow, and stop pulling as soon as the light turns blue or yellow. switch;
- 4 st: Pull all the lights between the s- th light and the t -th light (including the s- th light and the t- th light), and pull the switch in the order of which light it is, and the position in this action The light at s is the first light, and the light at position t is the last light.
Please calculate: the number of lights that are turned off when all sequences of actions are completed.
【enter】
The first line contains two integers L , n .
Next n lines, each line contains three integers op , s , t , where op represents the kind of action, and s and t represent the start and end positions of the action respectively.
【Output】
A line containing an integer representing the answer.
【Input sample】
10 2
4 2 8
2 1 9【Output sample】
5[Detailed code explanation]
#include <bits/stdc++.h>
using namespace std;
int l, n, op, s, t, ans=0;
int a[100005]={0};
int main()
{
cin >> l >> n;
for (int i=1; i<=n; i++) {
cin >> op >> s >> t;
if (op==1) {
for (int i=s; i<=t; i++) {
a[i] = 0;
}
} else if (op==2) {
for (int i=s; i<=t; i++) {
if (a[i]!=0) {
while (true) {
if (a[i]==1 || a[i]==3) break;
a[i] = (a[i]+1)%5;
}
}
}
} else if (op==3) {
for (int i=s; i<=t; i++) {
while (true) {
if (a[i]==4 || a[i]==2) break;
a[i] = (a[i]+1)%5;
}
}
} else if (op==4) {
for (int i=s; i<=t; i++) {
a[i] = (a[i]+ i-s+1)%5;
}
}
}
for (int i=0; i<=l; i++) {
if (a[i]==0) ans++;
}
cout << ans << endl;
return 0;
}【operation result】
10 2
4 2 8
2 1 9
5