topic:
Given the head of a sorted linked list head
, remove all duplicate elements so that each element appears only once . Returns a sorted linked list .
Example 1:
输入:head = [1,1,2]
输出:[1,2]
Example 2:
输入:head = [1,1,2,3,3]
输出:[1,2,3]
answer:
class Solution:
def deleteDuplicates(self, head: Optional[ListNode]) -> Optional[ListNode]:
if not head:
return head
# 判断是否为空,如果是空的,则直接return
cur = head
# 创建一个新指针cur来使用
while cur.next:
# 当这个列表还没被遍历完时
if cur.val == cur.next.val:
cur.next = cur.next.next
# 如果当前val和下一个val相同,则把next指针指向下下个
elif cur.val != cur.next.val:
cur = cur.next
# 如果当前val和下一个val不同,则把当前指针指向下一个Node
return head