Idea analysis:
We demand n! , n!=n*(n-1)!, until the recursion termination condition 1! =1, the summary formula is as follows:
Implementation process
Code
#include <stdio.h>
int main()
{ int fac(int n); //fac函数声明
int n,y;
printf("输入一个整数:");
scanf("%d",&n); //输入要求阶乘的数
y=fac(n);
printf("%d!=%d\n",n,y);
return 0;
}
int fac(int n) //定义fac函数
{
int f;
if(n<0) //n不能小于0
printf("n<0,数据错误!");
else if(n==0||n==1) //n=0或,1时n!=1
f=1; //递归终止条件
else
f=fac(n-1)*n; //n>1时,n!=n*(n-1)
return(f);
}
Precautions
The variables in the program are of type
int
.
Int type data is allocated
4
bytes. The maximum number that can be represented is
2 147 483 647.
When
n=12
, the operation is normal and the output is
479 001 600
. If you enter
13
and try to find
13!,
you will not get the expected result because the result exceeds the maximum value of
int
type data.
The f, y
and
fac functions
can
be defined as
float
or
double
types to increase the range of numerical representation.