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induction formula
- The trigonometric functions of acute angles are simple and easy to find (easy to express)
- For any angle, there are certain relationships between its various trigonometric functions that need to be discussed
- The most basic and commonly used formula for inducing trigonometric functions
Same end angles
- In the Cartesian coordinate system, α , α + 2 k π \alpha,\alpha+2k\pia ,a+2kπ, k ∈ K k\in\mathbb{K} k∈If the terminal sides of K are the same, they are defined by trigonometric functions. It is easy to know that the two trigonometric functions are equal.
- cos ( α + 2 k π ) = cos α \cos(\alpha+2k\pi)=\cos\alphacos ( a+2 kp )=cosa
- sin ( α + 2 k π ) = sin α \sin(\alpha+2k\pi)=\sin\alphasin ( a+2 kp )=sina
- tan ( α + 2 k π ) = tan α \tan(\alpha+2k\pi)=\tan\alphatan ( a+2 kp )=tana
Internalization of trigonometric functions for any angle
- According to the relationship between the trigonometric functions of the same terminal angles, all absolute values exceed one cycle ( 2 π 2\pi2 π or− 2 π -2\pi− 2 π ) can be converted into an absolute value less than2 π 2\pi2 π angle to calculate
Opposite angle
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About xxAngle that is symmetrical about the x- axis
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a \alphaThe opposite angle of α is− α -\alpha− a
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Obviously, the terminal sides of opposite angles are about xxThe x- axis is symmetrical. According to the definition of trigonometric functions, we have
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cos ( − α ) \cos(-\alpha)cos ( − α ) =cos α \cos\alphacosa
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sin ( − α ) \sin(-\alpha)sin ( − α ) =− sin α -\sin\alpha−sina
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tan ( − α ) \tan(-\alpha)tan ( − α ) =sin ( − α ) / cos ( − α ) \sin(-\alpha)/\cos(-\alpha)sin ( − α ) /cos ( − α ) =− tan α -\tan\alpha−tana
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summary
- cos α \cos\alphacosα is an even function, andsin α , tan α \sin\alpha,\tan\alphasina ,tanα is an odd function
Negative angle normalization of any angle
- From the conclusion of opposite angles, any negative angle can be converted into a positive angle to calculate and express
- For example cos ( − π 4 ) \cos(-\frac{\pi}{4})cos(−4p) =cos π 4 \cos\frac{\pi}{4}cos4p; sin ( − 7 π 3 ) \sin(-\frac{7\pi}{3})sin(−37 p.m) =− sin 7 π 3 -\sin\frac{7\pi}{3}−sin37 p.m, tan ( − π 3 ) \tan(-\frac{\pi}{3})tan(−3p) =− tan π 3 -\tan\frac{\pi}{3}−tan3p
Origin symmetry angle
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Angle α \alphaThe starting side of α is xxIn the rectangular coordinate system of the positive x -axis,α \alphaThe angle corresponding to the terminal side of α with respect to the terminal side of the origin is expressed as α + ( 2 k + 1 ) π \alpha+(2k+1)\pia+( 2k _+1 ) πψα + ( 2 k − 1 ) π \alpha+(2k-1)\pia+( 2k _−1)π, k ∈ Z k\in\mathbb{Z} k∈Z ; Let’s call this type of angleα \alphaThe origin symmetry angleof α
- In [ 0 , 2 π ) [0,2\pi)[0,α \alphawithin 2 π )The terminal side of α is symmetrical about the origin and is expressed asα ± π \alpha\pm{\pi}a±Pi
- Then according to the formula for generating angles with the same terminal side, we get the expression for the symmetrical angle at the origin.
- The coordinate signs of the points on the two terminal edges that are symmetrical about the origin are inverted.
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a \alphaThe symmetry angle between α and its originα + ( 2 k + 1 ) π \alpha+(2k+1)\pia+( 2k _+1 ) Trigonometric function relationship of π :
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cos ( α + ( 2 k + 1 ) π ) \cos(\alpha+(2k+1)\pi)cos ( a+( 2k _+1 ) π ) =− cos α -\cos\alpha−cosa
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sin ( α + ( 2 k + 1 ) π ) \sin(\alpha+(2k+1)\pi)sin ( a+( 2k _+1 ) π ) =− sin α -\sin\alpha−sina
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tan ( α + ( 2 k + 1 ) π ) \tan(\alpha+(2k+1)\pi)tan ( a+( 2k _+1 ) π ) =tan α \tan\alphatana
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Any angle sharpening
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Let the set of odd numbers be N 1 = { 2 k ∣ k ∈ Z } N_1=\set{2k|k\in{\mathbb{Z}}}N1={ 2k _∣k∈Z} , the even number set isN 2 = { 2 k + 1 ∣ k ∈ Z } N_2=\set{2k+1|k\in\mathbb{Z}}N2={ 2k _+1∣k∈Z}
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sin ( α + k π ) \sin(\alpha+k\pi)sin ( a+kπ ) ={ − sin α k ∈ N 1 sin α k ∈ N 2 \begin{cases}-\sin\alpha&k\in{N_1}\\ \sin\alpha&k\in{N_2}\end{cases}{ −sinasinak∈N1k∈N2
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cos ( α + k π ) \cos(\alpha+k\pi)cos ( a+kπ ) ={ − cos α k ∈ N 1 cos α k ∈ N 2 \begin{cases}-\cos\alpha&k\in{N_1}\\ \cos\alpha&k\in{N_2}\end{cases}{ −cosacosak∈N1k∈N2
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tan ( α + k π ) \tan(\alpha+k\pi)tan ( a+kπ ) =tan α \tan\alphatanα, k ∈ Z k\in\mathbb{Z} k∈Z
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After the above analysis and discussion, it can be seen that any angle can be transformed into α + k π \alpha+k\pia+kπ ,( ∣ α ∣ ⩽ π 2 ) (|\alpha|\leqslant\frac{\pi}{2})(∣α∣⩽2p) form
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Then according to α , − α \alpha,-\alphaa ,− The trigonometric function relationship of α is further transformed into[ 0 , π 2 ] [0,\frac{\pi}{2}][0,2p] to represent and calculate acute angle trigonometric functions
summary
- The first three sets of formulas above: (three terminal edge relationships correspond to three sets of formulas)
- Same end angles
- Opposite angle
- Origin symmetry angle
- Collectively called induced formulas , the formulas can be reasoned and memorized with the help of the terminal edge of any angle.
- The induction formula can be used to find the value of a trigonometric function or simplify a trigonometric function.
complementary angle
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Two angles are complementary ( α , π − α ) (\alpha,\pi-\alpha)( a ,Pi−α ) , then their terminal sides are aboutyyy- axis symmetry
- π − α \pi-\alphaPi−α can be viewed as− α + π -\alpha+\pi− a+π , that is, first aboutxxDraw− α -\alpha symmetrically about the x- axis− α final edge, and then make− α -\alpha− α is symmetric about the origin− α + π -\alpha+\pi− a+Pi
- Press α \alpha respectivelyWhen the terminal side of α is in four quadrants, it is proved that the same conclusion can be obtained: α , π − α \alpha,\pi-\alphaa ,Pi−αAbout yy_y- axis symmetry
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Known α \alphaα ,π − α \pi-\alphaPi−α are complementary angles, thensin ( π − α ) \sin(\pi-\alpha)sin ( p−α ) =sin α \sin\alphasina ? cos ( π − α ) \cos(\pi-\alpha)cos ( p−α ) =− cos α -\cos\alpha−cosa
- whereπ − α \pi-\alphaPi−α is equivalent toα \alphaαAbout xx_After symmetry on the x- axis, then symmetry about the origin
- sin ( π − α ) \sin(\pi-\alpha)sin ( p−α ) =− sin ( − α ) -\sin(-\alpha)−sin ( − α ) =− ( − sin α ) -(-\sin\alpha)−(−sinα ) =sin α \sin\alphasina
- Similarly, cos ( π − α ) \cos(\pi-\alpha)cos ( p−α ) =− cos ( − α ) -\cos(-\alpha)−cos ( − α ) =− cos α -\cos\alpha−cosa
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In short, the sine values of two complementary angles are equal, and the cosine values are opposite to each other.
与π 2 \frac{\pi}{2}2pTrigonometric functions related to angle expressions
- Formula (the latter two can convert α \alpha in the first twoα is replaced by− α -\alpha− α is obtained,5 ∼ 8 5\sim{8}5∼8 can be directly obtained from the ratio relationship between each and the first two formulas)
- cos ( α + π 2 ) \cos(\alpha+\frac{\pi}{2})cos ( a+2p) =− sin α -\sin\alpha−sina ?
- sin ( α + π 2 ) \sin(\alpha+\frac{\pi}{2})sin ( a+2p) =cos α \cos\alphacosa
- cos ( − α + π 2 ) \cos(-\alpha+\frac{\pi}{2})cos ( − a+2p) =sin α \sin\alphasina ?
- sin ( − α + π 2 ) \sin(-\alpha+\frac{\pi}{2})sin ( − a+2p) =cos α \cos\alphacosa
- tan ( α + π 2 ) \tan(\alpha+\frac{\pi}{2})tan ( a+2p)= − cot α -\cot{\alpha} −cota
- cot ( α + π 2 ) \cot(\alpha+\frac{\pi}{2})cot ( a+2p) =− tan α -\tan\alpha−tana
- tan ( − α + π 2 ) = cot α \tan(-\alpha+\frac{\pi}{2})=\cot{\alpha}tan ( − a+2p)=cota
- cot ( − α + π 2 ) \cot(-\alpha+\frac{\pi}{2})cot ( − a+2p) =tan α \tan\alphatana
α , α + π 2 \alpha,\alpha+\frac{\pi}{2}a ,a+2p
- Discuss α \alphaα和α + π 2 \alpha+\frac{\pi}{2}a+2ptrigonometric function relationship, we use
- The coordinates of the intersection point of the terminal side and the unit circle (the horizontal and vertical coordinates respectively reflect the angle α \alphasine and cosine of α )
- And the straight line y = ± xy=\pm x on the Cartesian coordinate systemy=± xauxiliary (transition)
- P ( x , y ) P(x,y) P(x,y )和Q ( y , x ) Q(y,x)Q(y,x ) with respect toy = xy=xy=xsymmetry _
- For example (2, 1) (2,1)(2,1), ( 1 , 2 ) (1,2) (1,2 ) ; also as( 1 , − 2 ) (1,-2)(1,−2), ( − 2 , 1 ) (-2,1) (−2,1)
- P ( x , y ) P(x,y)P(x,y )和Q ( − y , − x ) Q(-y,-x)Q(−y,− x ) abouty = − xy=-xy=−xsymmetry _ _
- For example ( 2 , 1 ) , ( − 1 , − 2 ) (2,1),(-1,-2)(2,1),(−1,− 2 ) ; also as( 1 , − 2 ) (1,-2)(1,−2), ( 2 , − 1 ) (2,-1) (2,−1)
- P ( x , y ) P(x,y) P(x,y )和Q ( y , x ) Q(y,x)Q(y,x ) with respect toy = xy=xy=xsymmetry _
- Coordinate relationships of points symmetrical about coordinate axes
- P ( x , y ) , Q ( x , − y ) P(x,y),Q(x,-y) P(x,y),Q(x,− y ) aboutxxx- axis symmetry
- P ( x , y ) , Q ( − x , y ) P(x,y),Q(-x,y) P(x,y),Q(−x,y ) Aboutyyy- axis symmetry
- In fact, α \alphaα can be transformed toα + π 2 \alpha+\frac{\pi}{2}through two appropriateaxial symmetry transformationsa+2p
- Let α \alphaThe terminal side α and the unit circle intersect at pointP ( cos α , sin α ) P(\cos\alpha,\sin\alpha)P(cosa ,sina )
- Take α \alphaDiscussion of the first quadrant angle of α formula as an example
- The first axial symmetry transformation is about the straight line y = xy=xy=x , the new coordinates obtained are denoted asMMM , from symmetry we can knowM ( sin α , cos α ) M(\sin\alpha,\cos\alpha)M(sina ,cosα ) , terminal edgeOM OMThe corresponding angle of OM : ( π 2 − α ) + 2 k π , k ∈ Z (\frac{\pi}{2}-\alpha)+2k\pi,k\in\mathbb{Z}(2p−a )+2 kp ,k∈Z
- The second axial symmetry transformation is about x = 0 x=0x=0 , the new coordinates obtained areNNN , byNNN andMMM with respect tox = 0 x=0x=0 symmetry, soN ( − sin α , cos α ) N(-\sin\alpha,\cos\alpha)N(−sina ,cosa ) ;角α + π 2 \alpha+\frac{\pi}{2}a+2pThe terminal edge is ON ONON ,N ( cos ( α + π 2 ) , sin ( α + π 2 ) ) N(\cos(\alpha+\frac{\pi}{2}),\sin(\alpha+\frac{\pi }{2}))N ( cos ( a+2p),sin ( a+2p))
- So cos ( α + π 2 ) \cos(\alpha+\frac{\pi}{2})cos ( a+2p) =− sin α -\sin\alpha−sina ? sin ( α + π 2 ) \sin(\alpha+\frac{\pi}{2})sin ( a+2p) =cos α \cos\alphacosa
- Using similar techniques, α \alpha can be completely summarizedThe same conclusion (formula) is established when α is in the four quadrants.
α , α − π 2 \alpha,\alpha-\frac{\pi}{2}a ,a−2p
- α − π 2 \alpha-\frac{\pi}{2}a−2p= − ( − α + π 2 ) -(-\alpha+\frac{\pi}{2})− ( − a+2p)
- It can be directly deduced from the formulas in the previous group, for example
- cos ( α − π 2 ) \cos(\alpha-\frac{\pi}{2})cos ( a−2p) =cos ( − ( − α + π 2 ) ) \cos(-(-\alpha+\frac{\pi}{2}))cos ( − ( − a+2p)) =cos ( − α + π 2 ) \cos(-\alpha+\frac{\pi}{2})cos ( − a+2p) =sin α \sin\alphasina
- sin ( α − π 2 ) \sin(\alpha-\frac{\pi}{2})sin ( a−2p) =sin ( − ( − α + π 2 ) ) \sin(-(-\alpha+\frac{\pi}{2}))sin ( − ( − a+2p)) =− sin ( − α + π 2 ) -\sin(-\alpha+\frac{\pi}{2})−sin ( − a+2p) =− cos α -\cos\alpha−cosa
- ⋯ \cdots ⋯
Summary@mantra
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Through research and induction on the induced formulas of trigonometric functions, people have summarized a set of formulas to quickly complete the conversion of the following form
- U ( α + k ⋅ π 2 ) U(\alpha+k\cdot{\frac{\pi}{2}})U ( a+k⋅2p), k ∈ Z k\in\mathbb{Z} k∈Z到 V ( α ) V(\alpha) V ( a )
- Inside U , VU,VU,V representssin , cos \sin,\cossin,A function name in cos , U, VU,VU,V may take the same function name
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Here is the most commonly used formula, mainly used for sin , cos \sin,\cossin,cos
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" Odd changes to even, unchanged, symbols look at the quadrants "
- Changes from odd to even remain unchanged:
- ifkk _k is an even number, thenU, VU, VU,The function names of V are the same, for example, they are allsin \sinsin or bothcos \coscos , that is,the function name remains unchanged
- ifkk _k is an odd number, the function name changes (sin → cos ; cos → sin \sin\to\cos;\cos\to{\sin}sin→cos;cos→sin)
- Symbols look at the quadrants:
- The sign refers to the plus or minus sign
- Change α \alphaα is regarded as an acute angle, and then judgeα + k ⋅ π 2 \alpha+k\cdot{\frac{\pi}{2}}a+k⋅2pThe quadrant where the terminal edge is located
- The sign of the terminal side (corresponding angle) under the trigonometric function U is VVThe symbol of V is simplythe same sign
- 例cos ( − 19 π 4 ) \cos(-\frac{19\pi}{4})cos(−419 p.m) =cos ( 19 4 π ) \cos(\frac{19}{4}\pi)cos(419π ) =cos ( 3 π 4 + 4 π ) \cos(\frac{3\pi}{4}+4\pi)cos(43 p.m+4 π ) =cos 3 4 π \cos{\frac{3}{4}\pi}cos43π =cos ( π 2 + π 4 ) \cos(\frac{\pi}{2}+\frac{\pi}{4})cos(2p+4p) =− sin π 4 -\sin\frac{\pi}{4}−sin4p= − 2 2 -\frac{\sqrt{2}}{2} −22
- Changes from odd to even remain unchanged:
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Other trigonometric functions can be converted into sin , cos \sin,\cossin,cos is calculated, so it is not necessary to remember
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If necessary, you can refer to other information for other formulas.