Topic 1053: Level 2 C Language-Average Calculation

Input 10 integers , find their average , and output the number of data that is greater than the average .

Output format

Number greater than average

Sample input

1 2 3 4 5 6 7 8 9 10

Sample output

5

This question is simple, just create an array and enter 10 numbers . Calculate the cumulative sum and then find the average , and then the for loop traverses the array data and compares it with the average . If it is larger, it is cnt+1. If it is not larger, there is no operation. Finally, just output the number directly.

//给10个数 求平均值然后有（）个大于平均值的个数
#include<iostream>
using namespace std;


int main(){
    int a[10]; //定义10个元素的数组
    int sum=0;
     for(int i=0;i<10;i++){  //录入10个数
         cin>>a[i];
         sum=sum+a[i]; //sum+=a[i]
     }
    sum=sum/10; //sum变成平均数
    
    int cnt=0;  //表示大于平均数的数
     for(int i=0;i<10;i++){
        if(a[i]>sum){
            ++cnt;  //++cnt比cnt++快（不考虑先后顺序的情况下）
        }
     }
     
cout<<cnt<<endl;  //输出超过平均数的个数
    
    return 0;
}