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1. Determine the size of any three numbers and arrange them from largest to smallest
a=input("请输入第一个数：")
b=input("请输入第二个数：")
c=input("请输入第三个数：")
a=int(a)
b=int(b)
c=int(c)
if a>b>c:
print(a,b,c)
elif a>c>b:
d=c;c=b;b=d
print(a,b,c)
elif b>a>c:
d=b;b=a;a=d
print(a,b,c)
elif b>c>a:
d=b;e=c;b=e;c=a;a=d
print(a,b,c)
elif c>a>b:
d=c;e=a;f=b;c=f;b=e;a=d
print(a,b,c)
elif c>b>a:
d=c;c=a;a=d
print(a,b,c)
else:
print(a,b,c)or
a=input("请输入第一个数：")
b=input("请输入第二个数：")
c=input("请输入第三个数：")
a=int(a)
b=int(b)
c=int(c)
if a>b>c:
print(a,b,c)
elif a>c>b:
print(a,b,c)
elif b>a>c:
print(a,b,c)
elif b>c>a:
print(a,b,c)
elif c>a>b:
print(a,b,c)
elif c>b>a:
print(a,b,c)
else:
print(a,b,c)2. Determine leap year
i=int(input("请输入年份："))
if ((i%4==0) and (i%100!=0)):
print("%d年是闰年"%i)
else:
print("%d年不是闰年"%i)3. Grades are divided by grade
score=int(input("请输入您的成绩："))
def func(score):
if score >100 or score <=0:
return"wrong score .must between 0 and 100."
elif score >= 90:
return"A"
elif score >= 80:
return "B"
elif score >= 70:
return "C"
elif score >=60:
return "D"
else:
return "E"
print(func(score))
或者用嵌套选择结构
score=int(input("请输入您的成绩："))
def func(score):
degree = "DCBAAE"
if score >100 or score <=0:
return"wrong score .must between 0 and 100."
else:
index =(score-60)//10
if index >= 0:
return degree[index]
else:
return[-1]
print(func(score))
4. Calculate the value of 1 added to 100
s=0;n=1
while n<=100:
s=s+n
n=n+1
print(s)
或者用for-else语句配合使用
s=0
for i in range(1,101):
s=s+i
else:
print(s)更多源码、Python知识手册＋薇欣：16521527841 备注CSDN 无套路直接发
5.Print the following graphics
*
**
***
****
*****
i=1
while i<=5:
j=1
while j<=i:
print("*",end="")
j=j+1
print("\n")
i=i+16. Calculate the sum of odd numbers and even numbers from 1 to 100
n=1;sum_odd = 0;sum_even = 0
while n <= 100:
if (n%2==0):
sum_even = sum_even + n
else:
sum_odd = sum_odd + n
n=n+1
print("奇数和为%d,偶数和为%d" %(sum_odd,sum_even))
或者
sum_odd = 0;sum_even = 0
for n in range(1,101):
if (n%2==0):
sum_even = sum_even + n
else:
sum_odd = sum_odd + n
print("奇数和为%d,偶数和为%d" %(sum_odd,sum_even))7. If the procedure is as follows
for i in range(6):
print(i,end="*****")
i=i-2
print(i)
输出结果为
0*****-2
1*****-1
2*****0
3*****1
4*****2
5*****3更多源码、Python知识手册＋薇欣：16521527841 备注CSDN 无套路直接发
8.The procedure is as follows
a_list = ["a","b","apple","red"]
for i,v in enumerate(a_list):
print("列表的第%d个元素为%s" %(i+1,v))
输出结果为
列表的第1个元素为a
列表的第2个元素为b
列表的第3个元素为apple
列表的第4个元素为red9. Print the multiplication table
for i in range(1,10):
for j in range(1,i+1):
print("{0}*{1}={2}" .format(i,j,i*j),end=" ")
print()
输出结果
1*1=1
2*1=2 2*2=4
3*1=3 3*2=6 3*3=9
4*1=4 4*2=8 4*3=12 4*4=16
5*1=5 5*2=10 5*3=15 5*4=20 5*5=25
6*1=6 6*2=12 6*3=18 6*4=24 6*5=30 6*6=36
7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49
8*1=8 8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64
9*1=9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81
10.The procedure is as follows
for i in range(1,101):
if (i%7==0) and (i%5!=0):
print(i,end=" ")
输出结果为
7 14 21 28 42 49 56 63 77 84 91 98 11.As follows
for i in range(10):
if (i==5):
print("found it! i=%d" %i)
else:
print("not found it...")
输出结果为
found it! i=5
not found it...更多源码、Python知识手册＋薇欣：16521527841 备注CSDN 无套路直接发
12, as follows
for i in range(10):
if (i==5):
print("found it! i=%d" %i)
break
else:
print("not found it...")
输出结果为
found it! i=513, as follows
for i in range(5):
print("-----")
print (i)
输出结果
-----
0
-----
1
-----
2
-----
3
-----
414.As follows
for i in range(5):
print("----")
if (i==3):
continue
print(i)
输出结果
----
0
----
1
----
2
----
----
4更多源码、Python知识手册＋薇欣：16521527841 备注CSDN 无套路直接发
15.pass statement
for letter in "runoob":
if letter == "o":
pass
print("执行pass块")
print("当前字母：%s" %letter)
print("good bye")
输出结果为
当前字母：r
当前字母：u
当前字母：n
执行pass块
当前字母：o
执行pass块
当前字母：o
当前字母：b
good bye16#####
list = ["ding",123,"true",(1,2,3,"apple"),[1,"小明"],{"name":"ding"}]
print(list[0])
print(list[2])
print(list[1:4])
print(list[:5:2]) #倒着取后两个元素
print(list[-1:-3:-1])
print()
print(list[len(list):]) ###利用切片方式实现列表的增加
list[len(list):] = [222]
print(list)
print()
list.append("good") #append() 在最后一个位置添加元素
print(list)
print()
list.insert(2,"food") #insert（）按照索引添加，元素插入后，后面的元素索引值会自动加1
print(list)
print()
list.extend("ABC") #extend() 迭代添加，在最后的位置，迭代每一个元素，依次添加
print(list)
print()
list.pop() #pop() 按照索引删除，默认删除最后一个
print(list)
list.pop(1) #删除索引值为1的元素
print(list)
print()
del list[:3] #利用切片删除元素
print(list)
print()
list1 = [3,5,7,9]
list1[:3] = [1,2,3] #利用切片修改列表元素
print(list1)
list1[:3] = []
print(list1)
list1 = list1(range(10))
print(list1)
list1[::2] = [0]*(len(list1)//2)
print(list1)更多源码、Python知识手册＋薇欣：16521527841 备注CSDN 无套路直接发
17.Judges’ scoring
list1 = []
n = int(input("请输入评委人数："))
while n <= 2:
print("评委人数需大于2")
n = int(input("请重新输入评委人数："))
p = int(input("请输入比赛人数："))
while p <= 1:
print("比赛人数需大于1")
p = int(input("请重新输入比赛人数："))
def check_score(score):
if score >= 0 and score <= 100:
return score
else:
print("分数不合法，请重新输入！")
score = int(input("请重新输入分数："))
score = check_score(score)
j = p
list2=[]
while j > 0 :
name = input("请输入选手序号：")
list2.append(name)
i = n
a = []
while i > 0:
score = check_score(int(input("输入评委打分分数：")))
a.append(score)
i -= 1
avg_score = (sum(a) - min(a) - max(a)) / (n-2)
list1.append([name,avg_score])
j -= 1
print(list1)
for i in range(p):
print("选手序号：", list2[i])
print("平均分：", list1[i][1])
ll=[]
for i in range(p):
ll.append(list1[i][1])
ll.sort(reverse=True)
print(ll)18. Calculate real solutions to quadratic equations of one variable
#coding=utf-8
import math
a=int(input("请输入方程系数a的值"))
b=int(input("请输入方程系数b的值"))
c=int(input("请输入方程系数c的值"))
if ((b*b-4*a*c)>=0)and((a!=0)):
x1=(-b+math.sqrt(b*b-4*a*c))/(2*a)
x2=(-b-math.sqrt(b*b-4*a*c))/(2*a)
print("方程%+d*x*x%+d*x%+d=0的两个实数解为：x1=%+.2f,x2=%+.2f"%(a,b,c,x1,x2))
else:
print("方程%+d*x*x%+d*x%+d=0无实数解"%(a,b,c))19.Day of the week
n="1,2,3,4,5,6,7"
data="一 二 三 四 五 六 日"
i=input("请输入阿拉伯数字1-7的任意一个数字:")
if i in n:
a=data[n.index(i)]
print("星期{}" .format(a))更多源码、Python知识手册＋薇欣：16521527841 备注CSDN 无套路直接发