Article directory
- Taobao store
- Fibonacci Phoenix Tail
1. Taobao store IO link
Ideas for this question: This question is a simple grammar question, just follow the meaning of the question.
#include <iostream>
using namespace std;
int main()
{
int arr[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int year1,month1,day1,year2,month2,day2;
while(cin>>year1>>month1>>day1>>year2>>month2>>day2)
{
int ret=0;
day1--;//1号到1号也会盈利一天,所以提前将day1减一天方便直接做减法计算能盈利的天数
while(year1<year2||month1<month2)
{
//如果前者的日期和后者的日期还不在同一个年月,则ret累加day1到月底的盈利
//如果是闰年的2月则一共29天,否则直接使用arr数组