C language: Write a program to output the number of all daffodils

Analysis: The definition of the narcissus number is the three-digit sum of the digits equal to the number itself.

We first need to create a loop that can output all three-digit numbers;

We also need to establish a judgment condition. Every time a number is output, judge whether it is a narcissus number. If it is, output it. If not, continue the loop without outputting it.

You also have to find a way to separate the three digits before you can make a judgment.

The source code is as follows and can be copied:

#include<stdio.h>
int main()
{
    int number, a, b, c;
    for(number=100;number<=999;number++)//输出所有的三位数
    { 
        a = number / 100;//取得百位数
        b = number % 100 / 10;//取得十位数
        c = number % 10;//取得个位数
        if (number == a * a * a + b * b * b + c * c * c)//判断是否为水仙花数
            printf("%5d", number);
    }
    return 0;
}

Of course, the code is not unique, the following code is also possible:

#include<stdio.h>
int main()
{
    int i, a, b, c;
    for(i=100;i<1000;i++)
    {
        a = i / 100;
        b = (i - a * 100) / 10;
        c = i % 10;
        if (a * a * a + b * b * b + c * c * c == i)
            printf("%d ", i);


    }
    return 0;
}

If you want to output all the daffodil numbers on the form in the format of 2 numbers per line, then:

#include<stdio.h>
int main()
{
    int i, a, b, c,n=0;
    for(i=100;i<1000;i++)
    {
        a = i / 100;
        b = (i - a * 100) / 10;
        c = i % 10;
        if (a * a * a + b * b * b + c * c * c == i)
        {
            printf("%d ", i);
            n++;
            if (n % 2 == 0)
                printf("\n");
        }


    }
    return 0;
}