Take the numbers 2, 0, 1, and 9 in each digit of 2019 as the first 4 items of a sequence, and use them to construct an infinite sequence, where the nth (>4) item is the unit digit of the sum of the first 4 items. For example, the fifth item is 2, because 2+0+1+9=12, the unit digit is 2.
For this question, you are asked to write a program to list the first n items of this sequence.
Input format:
The input gives a positive integer n (≤1000).
Output format:
Print the first n items of a sequence on one line, without spaces between numbers.
Input sample:
10
Sample output:
2019224758
Pit point: N may be less than 4
#include<cstdio>
#include<set>
#include<map>
#include<cmath>
#include<cstring>
#include<iostream>
#include<queue>
#include<algorithm>
using namespace std;
int main(){
char s[5] = "2019";
queue<int> nums;
nums.push(2);
nums.push(0);
nums.push(1);
nums.push(9);
int N,sum=12,num;
cin>>N;
if(N<=4) {
for(int i=0;i<N;i++){
cout<<s[i];
}
}else{
cout<<"2019";
}
N=N-4;
for(int i=1;i<=N;i++){
num = sum%10;
sum = sum - nums.front() + num;
nums.pop();
nums.push(num);
cout<<num;
}
return 0;
}