Several ways of oracle row to column and column to row

1. Prepare data: REST table

-- 创建表REST
CREATE TABLE REST (
  "ID" NUMBER,
  "AMOUNT" NUMBER(19,0),
  "MONTH" VARCHAR2(255 BYTE)
);

--执行添加数据语句
INSERT INTO "CERPAWCSADM"."REST" VALUES ('1', '100', 'Jan');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('1', '100', 'Feb');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('1', '66', 'Mar');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('1', '77', 'Jun');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('1', '88', 'Dec');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('1', '12', 'Aug');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('2', '22', 'Feb');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('2', '33', 'Apr');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('2', '232', 'Jul');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('2', '43', 'Sep');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('2', '544', 'Oct');
INSERT INTO "CERPAWCSADM"."REST" VALUES ('2', '65', 'Nov');

2. Query data

 3. Row to column

Method 1: Use case when then method

case condition

when value 1 then return value 1

when value 2 then return value 2

..........

else default value

end

-- 使用case when 方式
SELECT
	id,
	sum( CASE month WHEN 'Jan' THEN amount ELSE 0 END ) AS Jan_amount,
	sum( CASE month WHEN 'Feb' THEN amount ELSE 0 END ) AS Feb_amount,
	sum( CASE month WHEN 'Mar' THEN amount ELSE 0 END ) AS Mar_amount,
	sum( CASE month WHEN 'Apr' THEN amount ELSE 0 END ) AS Apr_amount,
	sum( CASE month WHEN 'May' THEN amount ELSE 0 END ) AS May_amount,
	sum( CASE month WHEN 'Jun' THEN amount ELSE 0 END ) AS Jun_amount,
	sum( CASE month WHEN 'Jul' THEN amount ELSE 0 END ) AS Jul_amount,
	sum( CASE month WHEN 'Aug' THEN amount ELSE 0 END ) AS Aug_amount,
	sum( CASE month WHEN 'Sep' THEN amount ELSE 0 END ) AS Sep_amount,
	sum( CASE month WHEN 'Oct' THEN amount ELSE 0 END ) AS Oct_amount,
	sum( CASE month WHEN 'Nov' THEN amount ELSE 0 END ) AS Nov_amount,
	sum( CASE month WHEN 'Dec' THEN amount ELSE 0 END ) AS Dec_amount 
FROM
	REST 
GROUP BY
	id 

case when another way:

        case when condition = value 1 then return value 1 

        case when condition = value 1 then return value 1 

        else default value

        end

	SELECT
	id,
	sum( CASE  WHEN month ='Jan' THEN amount ELSE 0 END ) AS Jan_amount,
	sum( CASE  WHEN month = 'Feb' THEN amount ELSE 0 END ) AS Feb_amount,
	sum( CASE  WHEN month = 'Mar' THEN amount ELSE 0 END ) AS Mar_amount,
	sum( CASE  WHEN month = 'Apr' THEN amount ELSE 0 END ) AS Apr_amount,
	sum( CASE  WHEN month = 'May' THEN amount ELSE 0 END ) AS May_amount,
	sum( CASE  WHEN month = 'Jun' THEN amount ELSE 0 END ) AS Jun_amount,
	sum( CASE  WHEN month = 'Jul' THEN amount ELSE 0 END ) AS Jul_amount,
	sum( CASE  WHEN month = 'Aug' THEN amount ELSE 0 END ) AS Aug_amount,
	sum( CASE  WHEN month = 'Sep' THEN amount ELSE 0 END ) AS Sep_amount,
	sum( CASE  WHEN month = 'Oct' THEN amount ELSE 0 END ) AS Oct_amount,
	sum( CASE  WHEN month = 'Nov' THEN amount ELSE 0 END ) AS Nov_amount,
	sum( CASE  WHEN month = 'Dec' THEN amount ELSE 0 END ) AS Dec_amount 
FROM
	REST 
GROUP BY
	id 

The result is:

Method 2: Use the decode function

decode function: DECODE(condition, value 1, return value 1, value 2, return value 2, value 3, return value 3, . . . else default value)

Meaning: if condition = value 1 then return value 1 elsif condition = value 2 then return value 2 else (default value) endif

--	使用decode函数
SELECT
	id,
	sum( decode( month, 'Jan', amount, 0 ) ) Jan_amount,
	sum( decode( month, 'Feb', amount, 0 ) ) Feb_amount,
	sum( decode( month, 'Mar', amount, 0 ) ) Mar_amount,
	sum( decode( month, 'Apr', amount, 0 ) ) Apr_amount,
	sum( decode( month, 'May', amount, 0 ) ) May_amount,
	sum( decode( month, 'Jun', amount, 0 ) ) Jun_amount,
	sum( decode( month, 'Jul', amount, 0 ) ) Jul_amount,
	sum( decode( month, 'Aug', amount, 0 ) ) Aug_amount,
	sum( decode( month, 'Sep', amount, 0 ) ) Sep_amount,
	sum( decode( month, 'Oct', amount, 0 ) ) Oct_amount,
	sum( decode( month, 'Nov', amount, 0 ) ) Nov_amount,
	sum( decode( month, 'Dec', amount, 0 ) ) Dec_amount 
FROM
	REST 
GROUP BY
	id 

The result is the same as method 1

Method 3: Use the pivot function

pivot
(
<aggregation function> (column to be aggregated)
for <column to be converted> in (column value to be converted as column name to be converted to)

SELECT
	* 
FROM
	 REST pivot (
		SUM(amount) FOR month IN (
			'Jan' AS Jan_amount,
			'Feb' AS Feb_amount,
			'Mar' AS Mar_amount,
			'Apr' AS Apr_amount,
			'May' AS May_amount,
			'Jun' AS Jun_amount,
			'Jul' AS Jul_amount,
			'Aug' AS Aug_amount,
			'Sep' AS Sep_amount,
			'Oct' AS Oct_amount,
			'Nov' AS Nov_amount,
			'Dec' AS Dec_amount 
		) 
	);

The result is: This result will find that if the data is empty and no value is assigned to 0

 The following method solves the problem of turning null into 0

SELECT
	NVl(Jan_amount,0) Jan_amount,
	NVl(Feb_amount,0) Feb_amount,
	NVl(Mar_amount,0) Mar_amount,
	NVl(Apr_amount,0) Apr_amount,
	NVl(May_amount,0) May_amount,
	NVl(Jun_amount,0) Jun_amount,
	NVl(Jul_amount,0) Jul_amount,
	NVl(Aug_amount,0) Aug_amount,
	NVl(Sep_amount,0) Sep_amount,
	NVl(Oct_amount,0) Oct_amount,
	NVl(Nov_amount,0) Nov_amount,
	NVl(Dec_amount,0) Dec_amount
FROM
	 REST pivot (
		SUM(amount) FOR month IN (
			'Jan' AS Jan_amount,
			'Feb' AS Feb_amount,
			'Mar' AS Mar_amount,
			'Apr' AS Apr_amount,
			'May' AS May_amount,
			'Jun' AS Jun_amount,
			'Jul' AS Jul_amount,
			'Aug' AS Aug_amount,
			'Sep' AS Sep_amount,
			'Oct' AS Oct_amount,
			'Nov' AS Nov_amount,
			'Dec' AS Dec_amount 
		) 
	);

The result is the same as method 1:

4. Column to row

Add the unpivot function to the original sql statement of the above pivot method to convert the columns into rows. In the unpivot function, amount: indicates the data converted from columns to rows

month: Indicates the column name after converting from column to row

select * from REST
pivot (sum(amount) for month in (
			'Jan' AS Jan_amount,
			'Feb' AS Feb_amount,
			'Mar' AS Mar_amount,
			'Apr' AS Apr_amount,
			'May' AS May_amount,
			'Jun' AS Jun_amount,
			'Jul' AS Jul_amount,
			'Aug' AS Aug_amount,
			'Sep' AS Sep_amount,
			'Oct' AS Oct_amount,
			'Nov' AS Nov_amount,
			'Dec' AS Dec_amount 
))
unpivot ( amount for month in(Jan_amount,Feb_amount,Mar_amount,Apr_amount,May_amount,Jun_amount,Jul_amount,Aug_amount,Sep_amount,Oct_amount,Nov_amount,Dec_amount));

The result is:

  

5. Directly use the unpivot function -- column transfer

Prepare data: TEST table

CREATE TABLE TEST (
  "ID" NUMBER(12,0) NOT NULL,
  "JAN" VARCHAR2(255 BYTE),
  "FEB" VARCHAR2(255 BYTE),
  "MAR" VARCHAR2(255 BYTE),
  "APR" VARCHAR2(255 BYTE),
  "MAY" VARCHAR2(255 BYTE),
  "JUN" VARCHAR2(255 BYTE),
  "JUL" VARCHAR2(255 BYTE),
  "AUG" VARCHAR2(255 BYTE),
  "SEP" VARCHAR2(255 BYTE),
  "OCT" VARCHAR2(255 BYTE),
  "NOV" VARCHAR2(255 BYTE),
  "DEC" VARCHAR2(255 BYTE)
);
-- 插入数据
INSERT INTO "CERPAWCSADM"."TEST" VALUES ('1', '33', '2', '3', '4', '5', '6', '7', '8', '9', '99', '8', '6');
INSERT INTO "CERPAWCSADM"."TEST" VALUES ('2', '22', '3', '4', '6', '5', '7', '0', '7', '22', '21', '343', '76');
INSERT INTO "CERPAWCSADM"."TEST" VALUES ('3', '88', '3', '4', '5', '7', '9', '7', '2', '2', '231', '56', '78');

Query data

column to row sql

SELECT
	* 
FROM TEST
	unpivot ( amount for month in(JAN,FEB,MAR,APR,MAY,JUN,JUL,AUG,SEP,OCT,NOV,DEC));

 The result is:

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Origin blog.csdn.net/SUMMERENT/article/details/129562622