Array deduplication method new Set

Divided into two cases: 1 ordinary array; 2 object array

1 ordinary array

const arr=[1,2,3,2,5,6,3]
const newarr=[...new Set(arr)]
console.log(newarr)//[1,2,3,5,6]

2 object array, if there is the following array

const data = [
  { name: '张三', mobile: '13811112222', idCard: '1234567890' },
  { name: '李四', mobile: '13911113333', idCard: '2345678901' },
  { name: '王五', mobile: '13811112222', idCard: '3456789012' },
  { name: '赵六', mobile: '13711114444', idCard: '4567890123' },
  { name: '钱七', mobile: '13911113333', idCard: '5678901234' }
];

The purpose of the operation is to filter out records with unique mobile fields

First take out all the mobile field values ​​​​in the data

const mobile=data.map(item=>item.mobile)

The second step is to deduplicate mobile

const newmobile=[...new Set(mobile)]

The third step is to traverse the data with the value in newmobile and filter out the corresponding records

const newdata=mobilenew.map(item=>{
return data.find(item=>item.mobile===item)
})

Complete code implementation

const data = [
  { name: '张三', mobile: '13811112222', idCard: '1234567890' },
  { name: '李四', mobile: '13911113333', idCard: '2345678901' },
  { name: '王五', mobile: '13811112222', idCard: '3456789012' },
  { name: '赵六', mobile: '13711114444', idCard: '4567890123' },
  { name: '钱七', mobile: '13911113333', idCard: '5678901234' }
];
const mobile=data.map(item=>item.mobile)
const mobilenew=[...new Set(mobile)]
const newdat=mobilenew.map(item=>{
	return data.find(itmes=>itmes.mobile===item)
})
console.log(newdat)
// [
//   { name: '张三', mobile: '13811112222', idCard: '1234567890' },
//   { name: '李四', mobile: '13911113333', idCard: '2345678901' },
//   { name: '赵六', mobile: '13711114444', idCard: '4567890123' }
// ]